- #1
Genericcoder
- 131
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Hi,
I just want to make sure my intuition is correct for why capacitors add normally when placed in parrallel and add reciprocally when placed in series.
In parrallel they add normally for example
C = C1 + C2 + C3;
Because when placed in parrallel the right hand plate share same Voltage as left hand plate,so the charge acquired would be
CV = C1V + C2V + C3V + C4V;
C = C1 + C2 + C3 + C4;
When you place them in series take 3 capacitors C1,C2,C3 where C1 is on the left C2 is in the middle and C3 is on the right handside.
So when you place them in the circuit C1 will acquire a positive charge so C3 will also acquire negative charge,and since they are neutral their will be also a negative charge on left side of C3,and Positive and negative on the right of C2 and on the left of C2;
So they all share same current:-
Q / C = Q/C1 + Q/C2 + Q/C3;
1/C = 1/C1 + 1/C2 + 1/C3;
I just want to make sure that this intuition is correct.
I just want to make sure my intuition is correct for why capacitors add normally when placed in parrallel and add reciprocally when placed in series.
In parrallel they add normally for example
C = C1 + C2 + C3;
Because when placed in parrallel the right hand plate share same Voltage as left hand plate,so the charge acquired would be
CV = C1V + C2V + C3V + C4V;
C = C1 + C2 + C3 + C4;
When you place them in series take 3 capacitors C1,C2,C3 where C1 is on the left C2 is in the middle and C3 is on the right handside.
So when you place them in the circuit C1 will acquire a positive charge so C3 will also acquire negative charge,and since they are neutral their will be also a negative charge on left side of C3,and Positive and negative on the right of C2 and on the left of C2;
So they all share same current:-
Q / C = Q/C1 + Q/C2 + Q/C3;
1/C = 1/C1 + 1/C2 + 1/C3;
I just want to make sure that this intuition is correct.