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null void
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In the full wave centre tap rectifier, piv of diode require is twice of the input current of the transformer. I can't understand why is it twice when the source is only 1V-peak.
null void said:In the full wave centre tap rectifier, piv of diode require is twice of the input current of the transformer. I can't understand why is it twice when the source is only 1V-peak.
CT is the centre tap, and that is grounded here. When one winding on the transformer has a voltage V volts, the other winding has a terminal voltage of -V volts. The conducting diode has no voltage loss across it. Mark these on your diagram, and you'll see what the voltage is on the reverse biased rectifier.null void said:This is my just my assumption:
I consider the voltage drop at the resistance is same as the voltage drop at the reversed biased diode...am i right?
null void said:sorry my V is the peak voltage of the transformer
There are 2 identical secondary windings, and at any moment in time they produce identical voltages.
NascentOxygen said:There are 2 identical secondary windings, and at any moment in time they produce identical voltages. So if you say there are V volts across one, then there must also be V volts across the other (regardless of whether there is current being drawn or not).
So for the situation depicted, with V volts across the lower winding, this places B at -V volts with respect to the other end of that winding (which being connected to earth, we call 0 volts).
NascentOxygen said:I did mean that, because I was picturing a meter across each to measure the amplitude. I didn't want to complicate with phasing there, but mentioned it in parentheses later just in case OP was wondering.
null void said:So the tap play an important role? without it the piv will not be double?
null void said:
Same as this? Voltage inversed = 24v ?
Indeed. But I sensed that OP may not have a good grasp of "phasing". That's why I referred to it as polarity, as you'll note in my 1st and 2nd posts in this thread.sophiecentaur said:But surely it's the phasing that makes the whole thing work.
Many points may be emphasized to give a more thorough analysis, but I sensed that OP does not have too solid a grounding here. I kept to just the essentials to answer his* question, lest he get mired in indigestible detail.There is, of course, the extra point that needs to be emphasised and that is
null void said:You mean this? And the polarity of the the 2 source is same or opposite?
The polarity is as you have them drawn. (I'm not going to say whether that should be termed "the same" or "opposite" because it depends on how you view them.)null void said:You mean this? And the polarity of the the 2 source is same or opposite?
NascentOxygen said:Indeed. But I sensed that OP may not have a good grasp of "phasing". That's why I referred to it as polarity, as you'll note in my 1st and 2nd posts in this thread.
Many points may be emphasized to give a more thorough analysis, but I sensed that OP does not have too solid a grounding here. I kept to just the essentials to answer his* question, lest he get mired in indigestible detail.
Indeed. It means something to me, but is unlikely to add clarity to OPs understanding.sophiecentaur said:Perhaps it's the word "Relative".