If a point is a distance X from charge #1, how far is it from charge #2?phy43 said:Electric field at distance r for each charge
E=Kq/r^2
Instead of calling the distance r, call it X. Don't plug in numbers right away. (And μC = 10^-6, not 10^-9.)E_1=(9.0*10^9)(6*10^-9)/r^2
E_1 = 54/r^2
Instead of r, write the distance in terms of X and the distance between the charges.E_2=(9.0*10^9)(1*10^-9)/r^2
E_2 = 9/r^2
When the electric field is equal to zero for two charges, it means that the forces exerted by the two charges on each other cancel out. This can happen when the two charges have equal magnitude and opposite signs, or when they are positioned at equal distances from each other.
The electric field between two charges is calculated using Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Yes, the electric field can be zero for any number of charges as long as their positions and magnitudes are arranged in a way that the forces cancel out. This can happen in a variety of configurations, such as a line of charges with alternating signs or a ring of charges with equal magnitudes.
When the electric field is zero for two charges, it means that the charges are in a state of equilibrium. This is important in many practical applications, such as in electronic circuits, where the goal is to achieve a balance of charges to prevent excess current or voltage.
No, it is not possible for the electric field to be zero at all points between two charges. The electric field is only zero at a specific point in space where the forces cancel out. In other points between the two charges, the electric field will have a non-zero value.