- #1
jesusjones
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Homework Statement
2n-1
Sigma (3i+1) = n(6n-1)
i=0
prove for all positive n
Homework Equations
The Attempt at a Solution
It holds true for n=1
5=5
then P: m+1
2m+1
Sigma(3i+1) = (m+1)(6(m+1)-1) or 6m^2 + 11m + 5
i=0
then 2m+1
Sigma(3i+1) = m(6m-1) + (3(m+1)+1) + (3(m+2)+1) = 6m^2 + 5m + 11
i=0
I just cannot figure this out and it is driving me crazy. Please help clarify things. I even tried changing the first part to
2m
Ʃ(3(i-1)+1)
i=1
and still couldn't prove it.
Thanks for your time