Jeff Reid said:You'd have to base this on a jet that climbs while hovering, like a Harrier. The time it takes doesn't matter. Work done on the jet is the force times the distance the jet is moved.
Work done on the air is a different matter though. Even in a steady hover, a huge amount of work is done on the air, accelerating it downwards and increasing the total energy of the air, and a huge amount of energy is consumed while hovering, even though there is no work done on the jet itself.
Lift is the force that allows an airplane to stay in the air. It is generated by the wings as they move through the air at a certain angle of attack, creating a difference in air pressure between the upper and lower surfaces of the wing.
Lift is calculated by using the formula: L = 1/2 x p x V^2 x S x CL, where L is lift, p is the air density, V is the velocity, S is the wing area, and CL is the coefficient of lift. This formula takes into account the four main factors that affect lift: air density, velocity, wing size, and wing shape.
As an airplane's velocity increases, the amount of lift generated also increases. This is because the faster the airplane moves through the air, the more air passes over the wings, creating a greater difference in air pressure and thus, more lift.
The weight of an airplane affects its lift energy requirements in two ways. First, a heavier airplane will require more lift to stay in the air, meaning it will need to fly at a higher velocity. Second, a heavier airplane will also require more thrust to achieve and maintain that higher velocity.
As an airplane climbs to higher altitudes, the air density decreases, which means that the air is thinner and there is less air molecules for the wings to generate lift. This means that the airplane will need to increase its velocity to maintain the same amount of lift, resulting in a higher energy requirement.