Optical path difference of air wedge

In summary: Adding 2nt to the path travelled by the upper ray accounts for the extra distance it travels inside the wedge. The 0.5λ is due to the phase change of 180 degrees that occurs when the lower ray is reflected from the lower glass surface. This phase change is also known as the "quarter wave" interference. The phase change of 2nt, on the other hand, is due to both rays passing through the glass surface twice. This can be cancelled out by the 0.5λ phase change, leaving only a net phase change of 0.5λ.
  • #1
desmond iking
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Homework Statement



i can't understand why the optical path diffrence is 2nt+0.5λ. why is it so? the 0.5λ is due to the path difference change of 180 degree of when it is reflected lower ray when it is reflected from the lower glass surface... why there's also phase change of 2nt. since both ray pass thru the glass surface twice , so it should cancel each other , leaving only phase change of 0.5λ . Am i right?
yG2lyg0.png

here's the link :
http://astarmathsandphysics.com/ib-physics-notes/optics/ib-physics-notes-wedge-films.html

Homework Equations


The Attempt at a Solution

 
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  • #2
desmond iking said:

Homework Statement



i can't understand why the optical path diffrence is 2nt+0.5λ. why is it so? the 0.5λ is due to the path difference change of 180 degree of when it is reflected lower ray when it is reflected from the lower glass surface... why there's also phase change of 2nt. since both ray pass thru the glass surface twice , so it should cancel each other , leaving only phase change of 0.5λ . Am i right?
yG2lyg0.png

here's the link :
http://astarmathsandphysics.com/ib-physics-notes/optics/ib-physics-notes-wedge-films.html

Homework Equations


The Attempt at a Solution

The 2nt refers to the path difference in the space between the plates. You see that one ray travels an extra distance of 2t relative to the other, right? Here, n is the index of refraction of the material wedged between the two glass plates, not the index of refraction of the glass (so n is approximately 1 if it is air).
 
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  • #3
n is not index of refraction here http://physicsforums.bernhardtmediall.netdna-cdn.com/images/icons/icon6.gif

n is any general integer, and it's used to account for cancellation if path difference is λ/2, or λ+λ/2, or 2λ+λ/2, or 3λ+λ/2, or...

λ is the wavelength in the material comprising that wedge
 
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What is the optical path difference of an air wedge?

The optical path difference of an air wedge is the difference in the distance traveled by a light ray passing through the thickest and thinnest points of the wedge. This results in a phase difference between the two rays, causing interference patterns when the rays are recombined.

How is the optical path difference of an air wedge calculated?

The optical path difference can be calculated by multiplying the refractive index of the medium by the thickness of the wedge at the thickest point.

What factors affect the optical path difference of an air wedge?

The optical path difference of an air wedge is affected by the thickness of the wedge, the refractive index of the medium, and the angle at which the light rays enter the wedge. Changes in any of these factors can alter the interference pattern observed.

What is the significance of the optical path difference in interference patterns?

The optical path difference determines the phase difference between the light rays, which in turn affects the interference pattern observed. This can give information about the thickness and refractive index of the medium, and can also be used in applications such as measuring small distances.

How is the optical path difference of an air wedge used in practical applications?

The optical path difference of an air wedge is used in optical interferometers to measure small distances and in spectrometers to analyze the properties of materials. It is also used in the study of thin film interference and in the manufacturing of precision optical components.

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