- #1
Lindsayyyy
- 219
- 0
Hi everyone
Take a look at the drawing. Now I found out the differential equation for this is:
[tex] \mu \vec{r}''=-k \vec{r}[/tex] mu is the reduced mass
Now I shall show, with using the generel solution for this differential equation (in cartesian coordinates), that the differential equation looks like the following in polar coordinates:
[tex]mr''=-kr[/tex]
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I tried it with inserting the solution in the first equation and take a look if I can reform it to the solution which I shall find out, but I just don't get there. Any hints?
Thanks in advance
Homework Statement
Take a look at the drawing. Now I found out the differential equation for this is:
[tex] \mu \vec{r}''=-k \vec{r}[/tex] mu is the reduced mass
Now I shall show, with using the generel solution for this differential equation (in cartesian coordinates), that the differential equation looks like the following in polar coordinates:
[tex]mr''=-kr[/tex]
Homework Equations
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The Attempt at a Solution
I tried it with inserting the solution in the first equation and take a look if I can reform it to the solution which I shall find out, but I just don't get there. Any hints?
Thanks in advance