Diagonalize a Matrix A - Normalize eigenvectors

In summary: C that you use to get the eigenvalues that go in D. (Note: u1 and u2 are the eigenvalues)In summary, After struggling with a homework problem involving diagonalizing a matrix and normalizing eigenvectors, the conversation reveals that the definition of an eigenvalue and eigenvector is that the eigenvalue is a scalar such that when multiplied by the eigenvector, it results in a scaled version of the same vector. The process of diagonalizing a matrix involves finding an invertible matrix P and a diagonal matrix D such that the original matrix A can be written as A = PDP^-1
  • #1
DaVinci
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I have a homework problem here I am a little at a loss on due to not very good examples in class and the part of the book that explains them is 4 chapters ahead and loaded with words I just do not understand yet. :bugeye: If someone could give a definition or two and get me started on this bad boy, I'd appreciate it.

The problem itself is:

Diagonalize the matrix A below. Normalize the eigenvectors so that they are unit vectors.

[TEX]
A = \left( {\begin{array}{*{20}c}
3 & {\sqrt 5 } \\
{\sqrt 5 } & { - 1} \\
\end{array}} \right)
[/TEX]

Code above is in work to look right... until then... remove the :

A = 3 : sgrt(5)
::sqrt(5) : -1

Now that the problem is stated, I will show my thoughts and what I am lacking in...

Diagonalizing the matric is basically taking A and getting A', where a'11, a'22, and a'33 (the diagonal) are the eigenvalues.

Side Note: The only definition I have of an eigenvalue is "Matricies that are true with Hermetian Conjugate have all real eigenvalues". But how do you define a word using the same word in the definition? Google search brings up a ton of pages that confuse me. So I stopped looking there! I do know that they mean different things depending on their application... for instance in molecular vibrations they would be the frequency or in classical L=IW they would be the moments of inertia... but that gets away from my main issue.

Now the equations I have of diagonalizing a matrix is, knowing CC^-1 is a unit matrix, IC = CI'. I believe this is using the similarity transform.

Thats about where I stand. Do I simply create the unit matrix for C and multiply that by A and that will give me A' with my eigenvalues in the diagonal? If so, what would I do to normalize them? Or I guess the better question would be "What is normalization?"

Appreciate any insight. :biggrin:
 
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  • #2
Your text should have a theorem on diagonalizing a matrix, and examples on it. Try looking for the equation [itex]A = PDP^{-1}[/itex]. (The choice of letters used seems fairly universal)

You are also probably looking at the wrong spot for the definition of eigenvector and eigenvalue -- the definition is that [itex]\lambda[/itex] is an eigenvalue of A, and [itex]\vec{v}[/itex] an eigenvector (associated with that eigenvalue) iff [itex]A\vec{v} = \lambda\vec{v}[/itex]. You may have seen this equation in your text for finding eigenvalues: [itex]\det (A - \lambda I) = 0[/itex].
 
  • #3
I think I got the same equation in my notes but it is in the form...

I' = (C^-1)(I)(C) where C is some matrix such that CC^-1 is a unit matrix.

Anyway, I found a good resource on the internet and also plugged through my notes quite a bit and I got somewhere. I just do not know if I answer the question or if there is still more to be done. Of course, I could have the answers right here but do not know their place (meaning).

I got the eigenvalues for the problem to be u=4 and u=-2 from using the matrix:

3-u : sqrt(5)
sqrt(5) : -1-u

Note: Is there some convention that shows how you combine the matrix with u to get the above matrix? I've seen it done a few times without the explanation so I just know to subtract u from a11 and a22 but don't know WHY I do that...

So, plugging those eigenvalues into the equations generated by the matrix above, I end up with the following eigenvectors:

u=4
sqrt(5/6) : 1/sqrt(6)

u=-2
-1sqrt(6) : sqrt(5/6)

So, does this mean I am done? Did I diagonalize the matrix? Unfortunantly, I have not been instructed on what that actually means... what numbers go in a matrix with all 0's except where i=k? The eigenvalues are the diagonal or are the eigenvectors the diagonal?

I think I have all the math part worked out pretty good except knowing how to get the u in the matrix as I had said above. Now I just need to figure out what values go in the diagonalized matrix... and the definitions...

PS: Does the Latex Generator really take that long or did I convert to the wrong version of Latex from MathType?
 
  • #4
Well, algebraically, you've diagonalized a matrix A iff you've found an invertible matrix P and a diagonal matrix D such that [itex]A = PDP^{-1}[/itex].

This is related to similarity transformations -- geometrically we picture it as choosing a basis in which A is a diagonal matrix. In particular, that means the basis is formed entirely from eigenvectors. (A fact that let's you write down the matrix P)

The usual way to find all the eigenvectors is to simply solve the equation [itex]A\vec{v} = \lambda\vec{v}[/itex] for [itex]\vec{v}[/itex], for each eigenvalue.

(Note that's the same as solving [itex](A - \lambda I)\vec{v} = 0[/itex]. Do you see why?)
 
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  • #5
I did not want to try and type all this out in text so I will give a link to a .jpg that is a scan of the work I did. This will allow you to see all my work (I did not skip many steps on purpose) and see what I am looking at.

http://home.cfl.rr.com/radiowave/q3.jpg

Edit: Also, how would you find P and D matrix if your only given A? I understand their relationship... just not sure how to get them.
 
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  • #6
The results look right.

Do you know how to apply a change of basis? Try using those two eigenvectors as your basis vectors... (they are independent, right?)
 
  • #7
I am not sure on what you mean...

I found that the professor added the diagonalization contact to our current work in Chapter 3 (where we started the course Monday) from Chapter 10! So, after finding that in Chapter 10 and reading it, I am very clear on what the eigenvalues, eigenvectors, and the diagonal of the Matrix is. I am also clear now on what they label as [itex]C^-1MC = D[/itex] or as you were calling it with the [itex]PDP^-1[/itex].

The 'diagonalized' matrix actually turns out to be nothing more than having the elements of the matrix with i=k (a11, a22, a33, ect) are the eigenvalues.

I also found out how / why you take the original matrix and have the u appear in the equations. It is simply subtracting the right hand matrix to the left hand side of the equation to make it all = 0.

Yeah, once I found the place in the book that talks about this stuff it is all very clear now. Too bad I didnt know that from the beginning. :)

If you have a chance to pick up an extra book, I highly recommend the one we have. Very clear and understandable! Mathematical Methods in the Physical Sciences - 2e - Mary L Boas.
 

1. What is the purpose of diagonalizing a matrix?

Diagonalizing a matrix involves finding a new matrix that has the same eigenvalues as the original matrix, but with the eigenvectors as its columns. This allows for easier manipulation and analysis of the matrix.

2. How do you diagonalize a matrix?

To diagonalize a matrix, you must first find the eigenvalues and eigenvectors of the matrix. Then, you can use these eigenvectors to create a diagonal matrix by multiplying the inverse of the eigenvector matrix by the original matrix.

3. What is the significance of normalizing eigenvectors?

Normalizing eigenvectors means scaling them so that they have a length of 1. This is important because it makes the eigenvectors easier to work with and compare to each other. It also helps to avoid errors in calculations.

4. Can all matrices be diagonalized?

No, not all matrices can be diagonalized. Only square matrices that have distinct eigenvalues can be diagonalized. This means that the matrix must have as many unique eigenvalues as its size.

5. What are the benefits of diagonalizing a matrix?

Diagonalizing a matrix can make calculations and analysis easier and more efficient. It also allows for a better understanding of the matrix's properties, such as symmetry and invertibility. In some cases, diagonalization can also reveal important information about the matrix, such as its eigenvalues and eigenvectors.

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