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Bohr model of the atom

by connor415
Tags: atom, bohr, model
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Mar6-12, 11:33 AM
P: 24
Eisberg and Resnick says that the condition for stability of the atom is:

k Ze2/r2=mv2/r

What I fail to understand is why the Z isnt square too. I mean surely you have Z electrons interacting with Z protons which which would surely give q1q2=(Ze)(-Ze)=-Z2e2?

What am I missing?
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Philip Wood
Mar6-12, 03:34 PM
PF Gold
P: 964
No. They are dealing with a one electron atom. You might say: then it's hydrogen, so why not put Z = 1? They leave Z open so the same treatment will do for, an He+ ion and so on.

Incidentally the equation you give isn't really the condition for stability. It is the classical F = ma equation for circular orbits. The stability condition is Bohr's condition: mvr = n[itex]\hbar[/itex].

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