Oscillation Motion Frequency: Spring & Block

[SCI2007]

A spring is hung from the ceiling. When a block is attached to its end, it stretches 2.0 cm before reaching its new equilibrium length. The block is then pulled down slightly and released.
What is the frequency of oscillation?

I'm totally Stuck help would be appreciated...

 

[Astronuc]

Knowing that the weight of the block is mg, where m is the mass and g = 9.81 m/s² must = the spring force = k * 0.02 m,

thus m 9.81 m/s² = k 0.02 m

Then what is the relationship between angular frequency and k and m?

http://hyperphysics.phy-astr.gsu.edu/hbase/shm2.html#c2

 

[ogb p]

The frequency of oscillation in this scenario can be calculated using the equation f = 1/T, where f is the frequency and T is the period of oscillation. The period of oscillation can be determined by measuring the time it takes for the block to complete one full cycle of motion, from its initial position to its maximum displacement and back to its initial position. The frequency can then be calculated by dividing 1 by the period.

In this case, the initial displacement of the block is 2.0 cm, so we can measure the time it takes for the block to return to this position after being released. Let's say it takes 0.5 seconds for the block to complete one full cycle. Using the equation, f = 1/0.5 = 2 Hz. Therefore, the frequency of oscillation in this scenario is 2 cycles per second or 2 Hz.

It is important to note that the frequency of oscillation can also be affected by other factors such as the mass of the block and the stiffness of the spring. These variables can be manipulated to change the frequency of oscillation. Additionally, the frequency of oscillation will remain constant as long as the amplitude (maximum displacement) of the block remains the same.