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Explanation for moving fluids having lower pressure |
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| Aug8-12, 02:47 AM | #18 |
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Explanation for moving fluids having lower pressureThe circulation imposed on the flow by this trailing edge, viscosity-driven condition is what causes the difference in flow speed between the upper and lower surface of the wing. As stated earlier in this thread, there's absolutely no reason a given parcel of air from ahead of the wing needs to recombine behind it (and in fact it does not in practice), so the common explanation is bogus. However, the result is the same - the flow on the upper surface is moving faster, while the flow on the lower surface is moving slower. Once this velocity distribution is obtained, the derived pressure distribution (from the Bernoulli relation) is both accurate and sufficient to explain the airfoil's lift. The key is in getting the correct velocity distribution in the first place, and potential flow (which you mentioned) does a fairly good job so long as the reynolds number is fairly high and the flow is effectively incompressible, both of which are true for aircraft flying below about mach 0.3 (so long as they aren't tiny UAVs). |
| Aug8-12, 09:29 AM | #19 |
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Cjl your first paragraph is completely wrong. The kutta condition is simply a mathematical boundary condition to solve a potential flow field. It has nothing to do with viscosity or imposing circulation directly, though it will affect the circulation magnitude. In addition, flows with viscosity will not leave the trailing edge of an airfoil smoothly; the total pressure will not be recovered. This is one reason why the Bernoulli equation does not describe lift. The kutta condition pertains to ideal flows only.
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| Aug8-12, 09:39 AM | #20 |
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Gosh folks why so heavy?
This is what the OP last asked |
| Aug8-12, 09:42 AM | #21 |
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To answer that question: the coanda effect. I cant think of a way to describe it simply other than the "stickyness" of air.
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| Aug8-12, 09:08 PM | #22 |
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As for the statement that flows with viscosity won't leave the trailing edge smoothly? Why do you think that? Flows with viscosity can flow smoothly off the trailing edge just fine. Depending on the details, the boundary layer will typically be turbulent for most aircraft, true, but this is on the scale of millimeters - the overall flow pattern is still smooth and attached. I'm also not sure why you're bringing total pressure into this. It's true that there's energy loss in a boundary layer, but to a pretty good approximation, the flow outside of the boundary layer itself is inviscid and lossless (for aircraft). As a result, the Bernoulli relation can be used along with the air velocity just outside of the boundary layer to determine the pressure just outside the boundary layer (which can be found by running an inviscid simulation of the airfoil, or if you really want to be picky about it, you can replace the airfoil shape with a slightly modified shape that adds in the boundary layer displacement thickness). In boundary layers, the pressure gradient in the normal direction to the surface is minimal (and very frequently assumed to be zero), so knowing the pressure distribution just outside the boundary layer also tells you the pressure distribution inside the boundary layer, at the surface of the airfoil. If you know the pressure distribution at the surface of the airfoil, all you need to do is integrate around the airfoil to get the lift. Note that this entire process uses only potential flow (inviscid, incompressible, lossless) and the bernoulli relation, but it is very accurate at describing the lift generated by an airfoil at high reynolds number below mach 0.3. To answer your final sentence, the Kutta condition applies to pretty much every flow around a non-stalled airfoil. It isn't purely a theoretical construct - if anything, it's more of an empirical observation describing the behavior of flows around objects with a sharp trailing edge. By itself, it doesn't actually serve much of a purpose, but when combined with other fluid dynamic principles, it can be quite useful in determining the properties of the flow around an object. |
| Aug12-12, 09:55 PM | #23 |
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Also, I would like to show you why the Bernoulli equation does not correctly explain why lift is generated on a airfoil. Yes, it can be used as a mathematical approximation to a real flow, but it is a very misleading statement from a physical standpoint. Here is an example: Assume that the lift generated by an airfoil can be described entirely by the differences in velocities on the upper and lower surface. Lets also assume that we are flying at sea level under normal conditions. The equation describing the lift due to the average velocity gradient will be given by [itex]1/2 \rho (V_{top}^2 - V_{bot}^2) = L/S [/itex] ρ = air density L = Lift generated by the body (lets say wing for simplification) S = lifting surface area (wing area) V = velocity The equation will become with some substitution: [itex] V_{top}^2 - V_{bot}^2 = C_L V^2 [/itex] Assuming that the reference velocity for the lift coefficient (freestream) is equal to the velocity under the bottom half of the wing: [itex] V_{top} = \sqrt{C_L} V_{bot} [/itex] It is clear that when the lift coefficient is low (low angle of attack, flying a high speed with large wing area, cruise conditions) that the bernoulli principle describes lift sufficiently well. However, lets consider take off or landing conditions when the lift coefficient is large. For a specific example, consider a large airliner landing at 160 mph (74 m/s) with a lift coefficient of 4. The average velocity above the wing will be: [itex] V_{top} = 2*74 = 148 [m/s] [/itex] If the lift on this wing was due entirely to the differences in velocities above and below the wing, then the mach number at the top surface will be .43, and the bottom will be .215. It doesn't make physical sense that the mach number above the wing will be nearly twice the free-stream speed. Lift, therefore, cannot be described by the bernoulli principle alone. A better explanation is the conservation of momentum. SIDE NOTE:I wish I could find better/specific numbers, but these are ball-parked estimates from the internet. I know that triple slotted flaps, used on some large airliners, can have maximum lift coefficients around 6. Specifics are proprietary information sadly. |
| Aug13-12, 09:47 AM | #24 |
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I had a dream I made a stupid mistake and I was right. The math under the radical should be C L +1 making the results from my calculation Vtop = √5 * 74 =165 m/s or a Mach number of. 48. Again, physically unrealistic.
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| Aug13-12, 10:13 AM | #25 |
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S is different for top and bottom except for bricks. Also there is a significant variation of pressure over this area, both top and bottom. In fact the solution for pressure on the underside has a singularity without friction. |
| Aug13-12, 10:33 AM | #26 |
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The Kutta condition, as mathematically expressed in airfoil theory, is the means of imposing mathematically this physical reality. Flows modeled with viscosity do not need to "satisfy the Kutta condition" because they are, by default, already satisfied because a solution doesn't exist otherwise. Some may argue that by definition, it is needed to solve the inviscid flow field because without it, the solutions are of course trivial and aren't actually the solutions in which we are interested. I would count myself among those who would argue this. Recall the solution for the inviscid flow around a circular cylinder. The speed at the top and bottom of the cylinder (+/-90° from the forward stagnation point) is precisely twice the freestream velocity. This should give you some intuition into the fact that your example actually could happen. Even something as simple as a NACA 0012 at 0° AoA will accelerate the air to around u/U≈1.2 without even generating any lift. Put that at an angle of attack and that number will increase. |
| Aug14-12, 03:06 AM | #27 |
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Also, your Cl numbers seem too high to me. I'm not aware of any airfoil that can actually pull off a lift coefficient of 4, and 6 (your quoted number for a triple slotted) is unachievable by any normal means that I am aware of. One thing you might consider checking is the reference area - many aircraft use high lift systems that (sometimes dramatically) increase the area of the wing, so if you continue to use the clean wing area as the reference area, the Cl numbers will seem incredibly high (while in reality, the Cl might be a more reasonable 2-2.5 or so if the actual wing area with flaps extended were used). Studiot: In general, the wing surface area is considered to be the area projected onto a plane defined by the wing's chord line. It's true that the top has more area, but the area used for computations is basically the area that the wing would have if it were zero thickness and flat. |
| Aug14-12, 04:57 AM | #28 |
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The interaction between the object and the flow produces two orthogonal forces the lift perpendicular to the flow and the drag parallel to the flow. But the relative magnitude of these depends not only on the projected area but also on the angle between the plane of this area and the flow ie the angle of attack. Whether you attribute this to two projected areas in two orthogonal planes or by separately accounting for the angle is a matter of choice, but this needs to be defined. |
| Aug14-12, 05:48 PM | #29 |
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I am really upset because the internet died just as a posted a response. Here is a truncated and pissed off response of the major points I made:
boneh3ad: The Kutta condition does not apply to real flows - it can neither be satisfied nor unsatisfied. In theory introducing viscosity into the model will accurately predict the flow pattern. I also believe my statement about slight separation on most airfoils is a fair generalization (even if it is negligible for practical calculations) because total pressure is never fully recovered on a wing. A true stagnation point does not exist at the trailing edge. The argument you made about lift being dictated by the boundary layer, pressure distribution and angle of attack is somewhat trivial because those facts are true for anything that generates lift - even a brick. I already agreed with cjl by stating that the Kutta condition is a mathematical boundary condition based on observation. Also, your point about the velocity at the peak of the cylinder being twice the freestream flow is invalid because the discussion pertains to differences between the upper and lower surfaces of a wing. The difference in velocities for the case you described is 0 and no lift is generated. I used the freestream flow as the flow speed on the lower surface purely for simplicity. cjl At one point in time I had access to some information in which lift coefficients exceeding 5 were measured on certain flap configurations. I cannot disclose specifics (as this information may have accidentally fallen into my hands when it fell into my desk one evening), but a publicly available paper is: High-Lift Systems on Commercial Subsonic Airliners. If my Cl seems high consider safety requirements for emergency landings |
| Aug14-12, 08:00 PM | #30 |
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As for safety requirements for emergency landings? Those don't necessarily require a high Cl - they require the right combination of Cl, wing area, and acceptable landing speed. Modern airliners are actually going towards simpler high lift devices, along with lower Clmax values because modern airfoils perform much better at high speed, allowing for a larger wing area, higher aspect ratio, and less sweep for a given cruise speed. This increase in wing area and aspect ratio allows for lower landing and takeoff speeds without needing dramatic high lift devices, which allows for a simpler mechanical design as well. |
| Aug14-12, 08:46 PM | #31 |
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| Aug14-12, 09:57 PM | #32 |
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| Aug24-12, 10:47 AM | #33 |
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Sorry for the belated response. I recently moved about 400 miles from my old home and it took me about week to get things settled. Anyway, on to "business".
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| Aug24-12, 10:51 AM | #34 |
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Plus, I tried the Euler Solver. I got flow speeds about 4.5 x as fast between the top and the bottom surfaces. These points were inside the boundary layer though (the program uses Zhukovski transformations), so the difference between the top/bottom is probably slightly less. I also noticed that the flow below the surface was also less than the freestream velocity, invalidating one of the assumptions I made in the equation I wrote earlier.
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