- #1
bjgawp
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Right now, we're doing thermal physics.
For one of our assignments, the teacher asked us to make our own experiment and write on a lab on it. For this lab, we had to investigate a question she gave us:
If water is left in a container open to the air, its temperature will drop below the room temperature. What 2 factors determine the amount by which the temperature is depressed?
For one of the factors, I tried added increasing amounts of salt into various beakers with water with the same initial temperatures - hoping that the salt will interfere with the final temperature when I left it overnight. However, all the temperatures were still the same when I recorded them in the morning.
So now I'm stumped, what other factors can I test on that I can do at home - all I have is a thermometer and a beaker...
Thanks :)
For one of our assignments, the teacher asked us to make our own experiment and write on a lab on it. For this lab, we had to investigate a question she gave us:
If water is left in a container open to the air, its temperature will drop below the room temperature. What 2 factors determine the amount by which the temperature is depressed?
For one of the factors, I tried added increasing amounts of salt into various beakers with water with the same initial temperatures - hoping that the salt will interfere with the final temperature when I left it overnight. However, all the temperatures were still the same when I recorded them in the morning.
So now I'm stumped, what other factors can I test on that I can do at home - all I have is a thermometer and a beaker...
Thanks :)