A few questions relating to the cross product

In summary, the conversation discusses various questions related to vectors, arc length, and proving perpendicularity and parallelism. The steps to calculate arc length, the use of the Pythagorean theorem to prove perpendicularity, and the condition for parallel vectors are all discussed. The conversation also highlights the helpfulness of putting questions into a different form of media for better understanding.
  • #1
Spiffy
4
0
Ug. My first try at this and my whole post was deleted. Here goes again :)

Homework Statement



i) Two cities on the surface of the Earth are represented by position vectors that connect the location of each city to the centre of the earth. Assuming that the centre of the Earth is assigned the coordinates of the origin, and that the Earth is a perfect sphere, outline the steps that would lead to a calculation of the shortest distance between the two cities. Hint: How can you determine arc length?

ii) Prove A is perpendicular to B if |A+B| = |A-B|

iii) A||B if AxB=0


The Attempt at a Solution


i) well you have two vectors pointing outword tail to tail and an angle Θ in between them. What I don't really know is how to find the arc length as the hint wants me to. If someone could point me toward an equation i'll report with some progress

ii) It seems so obvious that I'm sure it's staring me in the face and I don't even know it. I have drawn on my paper A vector downward and B and -B vector going on at 90o degrees either way. So now I have one triangle made up of two others and the two triangles are obviously equal to each other, they share adj and opp sidelengths and therefore the hypotenuse must as well be equal in both. I don't kknow how to take this from my sketch to something a bit more formal and algebraic though..

iii) I know that its true because if they were parallel sinΘ would = 0. I have:
AxB = |A||B|sinΘ
If A and B are parallel Θ=0
RS: |A||B|sin0
= 0
therefore AxB=0 when A and B are paralell. Would you accept this?

I appreciate any light that can be shed on some of these questions. I know this website is going to be a valuable resource for myself now and in the future. Even just typing questions up here is helping. (I originally had 4 questions but solved one just by putting it into a different form of media) thanks a lot!
 
Physics news on Phys.org
  • #2
Welcome to PF!

Spiffy said:
Ug. My first try at this and my whole post was deleted. Here goes again :)

i) … Hint: How can you determine arc length?

ii) Prove A is perpendicular to B if |A+B| = |A-B|

iii) A||B if AxB=0

Ug! Welcome to PF! :smile:

i) arc-length = radius times angle (in radians)

(so arc-length for 2π angle is 2πr, as you'd expect! :wink:)​

ii) Hint: square each side!

iii) Your answer looks fine to me! :smile:
(I originally had 4 questions but solved one just by putting it into a different form of media) thanks a lot!
Yes, sometimes rewriting a question so that other people can understand it makes all the difference! :biggrin:

Ooog!
 
  • #3


I would like to commend you for your effort in attempting these questions. It is always important to ask questions and seek help when needed, especially when it comes to understanding mathematical concepts.

To answer your first question, to calculate the shortest distance between two points on a sphere (in this case, the Earth), you can use the formula for arc length: s = rΘ, where s is the arc length, r is the radius of the sphere, and Θ is the central angle (in radians). In this case, the radius would be the radius of the Earth, and the central angle can be calculated using the dot product of the two position vectors. The dot product gives you the cosine of the angle between the two vectors, and you can use inverse cosine (arccos) to find the angle.

For your second question, you are on the right track. To prove that A is perpendicular to B, you can use the Pythagorean theorem. If you square both sides of the given equation, you get (A+B)^2 = (A-B)^2. Expanding this and using the fact that A and B are perpendicular (meaning their dot product is 0), you can simplify the equation to show that A and B are indeed perpendicular.

For your third question, your reasoning is correct. If A and B are parallel, their cross product would be 0, which is what you showed in your proof. Therefore, A and B are parallel if and only if their cross product is 0.

I hope this helps and keep up the good work in your studies!
 

1. What is the cross product?

The cross product is a mathematical operation that takes two vectors as input and produces a third vector that is perpendicular to both of the input vectors. It is represented by the symbol "×" or "⨯".

2. How is the cross product calculated?

The cross product of two vectors, A and B, can be calculated using the following formula: A × B = (AyBz - AzBy, AzBx - AxBz, AxBy - AyBx).

3. What is the significance of the cross product?

The cross product is useful in many areas of mathematics and physics, such as calculating torque and angular momentum, determining the direction of a magnetic field, and finding the area of a parallelogram formed by two vectors.

4. Can the cross product be applied to any two vectors?

No, the cross product is only defined for three-dimensional vectors. It is also important to note that the order of the vectors matters, as the cross product is not commutative (i.e. A × B is not necessarily equal to B × A).

5. Are there any other ways to calculate the cross product?

Yes, there are other methods for calculating the cross product, such as using the determinant of a 3x3 matrix or using the vector triple product formula. However, the formula mentioned in question 2 is the most commonly used method.

Similar threads

Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Linear and Abstract Algebra
Replies
32
Views
3K
Replies
8
Views
820
  • Precalculus Mathematics Homework Help
Replies
5
Views
544
Replies
10
Views
709
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
20
Views
7K
Back
Top