- #1
fubag
- 105
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You and your lab partner devise a clever experiment to measure the force applied to a ball when it is thrown. You throw a 200-{g} ball vertically upward. A high-speed video image of the throw indicates your hand pushed on the ball for 0.32 {\rm s}. The ball rises to a maximum height of 7.23 {\rm m} above your hand.
Calculate the force applied.
I tried.
Y = 1/2at^2
so
7.23m = 1/2(9.81m/s/s)(t^2)
Solved for t = 1.2 seconds...
Now I know F = ma
so is it simply F = 0.2kg*9.81m/s/s?
Im not sure
Calculate the force applied.
I tried.
Y = 1/2at^2
so
7.23m = 1/2(9.81m/s/s)(t^2)
Solved for t = 1.2 seconds...
Now I know F = ma
so is it simply F = 0.2kg*9.81m/s/s?
Im not sure