most defiantly, that's how i first looked at it. from the looks of it though they haven't started studying energy yet (at least that's what i think) and i was ify on possible jumping ahead.Hootenanny said:Alternatively, one could consider the work-energy theorem
how can you be sure that the acceleration or retardation here is constant?Delzac said:When i comes to inclined slope like these part of the g is "filtered" off. Thus Draw out your free body diagram, resolve the g in the direction parrallel to the slope.
then use the formula V^2 = U^2 + 2as
Hope it helps.
EDITED version
sry ><
Is the acceleration due to gravity (approximately) constant here?castaway said:how can you be sure that the acceleration or retardation here is constant?
An inclined plane can help a car that has run out of gas by using its slope to allow the car to roll or slide down to a lower elevation, using the force of gravity to move the car forward without the need for gas.
The principle behind using an inclined plane for a car out of gas is that it can convert potential energy (stored energy in the car's elevated position) into kinetic energy (energy of motion) to move the car forward.
The ideal angle for an inclined plane to move a car out of gas can be determined by calculating the angle at which the force of gravity acting on the car is equal to the force of friction acting against it. This will result in the car moving at a constant speed down the inclined plane.
Yes, there are other factors to consider when using an inclined plane to move a car out of gas. These include the weight of the car, the coefficient of friction between the car and the surface of the inclined plane, and any external forces (such as wind) that may affect the motion of the car.
Yes, an inclined plane can be used for any type of car out of gas as long as the car has wheels and can be placed on the inclined plane. However, the effectiveness of using an inclined plane may vary depending on the weight and other factors mentioned above.