- #1
Kalie
- 46
- 0
A rock is tossed straight up with a velocity of +20m When it returns, it falls into a hole 10m deep.
What is the rock's velocity as it hits the bottom of the hole?
So basically it is asking for the impact speed right?
So that would be
Vf^2=Vi^2 +2adelta(s)
Vf^2=0+2*9.8*30.41
Vf^2=24.41
It says it is wrong. I know 30.41 is the right amount of the total meters in the fall since I solve another part and got the answer right. So that means that the kinematic equation is wrong so which would it be?
What is the rock's velocity as it hits the bottom of the hole?
So basically it is asking for the impact speed right?
So that would be
Vf^2=Vi^2 +2adelta(s)
Vf^2=0+2*9.8*30.41
Vf^2=24.41
It says it is wrong. I know 30.41 is the right amount of the total meters in the fall since I solve another part and got the answer right. So that means that the kinematic equation is wrong so which would it be?