Understanding PV Diagrams - Work

[tizzful]

Homework Statement

Calculate the work done by the gas during process 1-> 3-> 6.
Express your answer in terms of Po and Vo.

Homework Equations

W=integral(pv) from V1-V2
W=PVln(V2/V1)

The Attempt at a Solution

3Po*V*ln(3Vo/Vo)

I'm not sure what I'm doing wrong, it keeps telling me I'm off by a multiplicative factor.. Should I be using W=nRT ln(V2/V1) ?
ht tp://i33.photobucket.com/albums/d53/tizzful/151890.jpg (take out the space)

 

[tizzful]

Never mind, I solved it

 

[Moetasim]

I would first clarify the context of the problem. PV diagrams are typically used to represent the relationship between pressure (P) and volume (V) for a gas undergoing a thermodynamic process. Without knowing the specific details of the process 1->3->6, it is difficult to provide an accurate solution.

In general, the work done by a gas during a thermodynamic process can be calculated by integrating the product of pressure and volume over the entire process. In this case, you would need to know the pressure and volume at each point (1, 3, and 6) in order to accurately calculate the work done.

Additionally, the equation W=PVln(V2/V1) is only valid for an isothermal process (constant temperature). If the process is not isothermal, then you would need to use the more general equation W=nRT ln(V2/V1), where n is the number of moles of gas, R is the gas constant, and T is the temperature.

In conclusion, without more information about the specific process and the values of pressure and volume at each point, it is not possible to accurately calculate the work done by the gas. It is important to always clarify the context and assumptions of a problem before attempting to solve it.