The dot or cross product of two operators acting on a state

In summary, the conversation discusses the use of the Kronecker product to describe a system made up of two subsystems, how the number of elements in the resulting vector is determined, and the application of operators \hat{\mathbf{A}} and \hat{\mathbf{N}} to the atomic and photon states. The concept of tensor product of operators is also mentioned as a way to represent the combined operation of \hat{\mathbf{A}} and \hat{\mathbf{N}} on the system.
  • #1
Robert_G
36
0
If a system is made up by two subsystems, for example, the atom and the photon. and let's assume the state of the atoms is described by [itex]|\phi\rangle[/itex], while the state of the photons can be described by [itex]|n\rangle[/itex], The Kronecker product of the [itex]|\phi\rangle[/itex] and [itex]|n\rangle[/itex] can be used to describe the whole system. and that would be:

[itex]|\Psi\rangle=|\phi, n\rangle=|\phi\rangle\otimes|n\rangle[/itex]

I always treat the [itex]|\phi\rangle[/itex] and [itex]|n\rangle[/itex] as vectors, so the operation of [itex]\otimes[/itex] means the elements of the first vector (here [itex]|\phi\rangle[/itex]) times the "whole" following vector which is [itex]|n\rangle[/itex] here; that will gives us a vector which is [itex]|\phi, n\rangle[/itex]. so if the numbers of the elements of [itex]|\phi\rangle[/itex] and [itex]|n\rangle[/itex] is [itex]m[/itex] and [itex]n[/itex] respectively, the vector [itex]|\phi, n\rangle[/itex] has [itex]m\times n[/itex] elements.

now for example, we have two operators, [itex]\hat{\mathbf{A}}[/itex] and [itex]\hat{\mathbf{N}}[/itex], and they satisfy the following equations:
[itex]\hat{\mathbf{A}}|\phi\rangle=\mathbf{a}|\phi'\rangle[/itex]
[itex]\hat{\mathbf{N}}|n\rangle=\mathbf{n}|n'\rangle[/itex].

Of course, [itex]\hat{\mathbf{A}}[/itex] can only act on the atomic states, and [itex]\hat{\mathbf{N}}[/itex] can only act on the photons states.

Now, my question, what is [itex]\hat{\mathbf{A}}\cdot \hat{\mathbf{N}}|\phi, n\rangle[/itex], and what is [itex]\hat{\mathbf{A}}\times \hat{\mathbf{N}}|\phi, n\rangle[/itex]? The idea just not clear to me, if the operation [itex]\otimes[/itex] is involved.
if [itex]\hat{U}=\hat{\mathbf{A}}\cdot \hat{\mathbf{N}}[/itex], for example, how to write [itex]\langle \phi, n|\;|U|^2\; |\phi', n'\rangle[/itex] on the base of [itex]|\phi\rangle[/itex] and [itex]|n\rangle[/itex]?
 
Physics news on Phys.org
  • #2
You need the tensor product of operators. (See the section "Tensor product of linear maps".)
 
  • #3
strangerep said:
You need the tensor product of operators. (See the section "Tensor product of linear maps".)

are you talking about a section of a book?
 

1. What is the difference between the dot product and cross product of two operators?

The dot product of two operators is a scalar quantity, meaning it has only magnitude and no direction. It is calculated by multiplying the components of the two operators together and then summing them. On the other hand, the cross product of two operators is a vector quantity, meaning it has both magnitude and direction. It is calculated by taking the vector cross product of the two operators.

2. How do you calculate the dot product of two operators?

To calculate the dot product of two operators, you first need to find the components of each operator. Then, multiply the corresponding components of the two operators together and add them. The resulting value is the dot product.

3. What is the physical interpretation of the dot product of two operators?

The dot product of two operators represents the projection of one operator onto the other. It can also be thought of as a measure of the similarity or alignment between the two operators.

4. Can the dot product of two operators be negative?

Yes, the dot product of two operators can be negative. This occurs when the two operators are not aligned or have opposite directions.

5. How is the cross product of two operators related to the dot product?

The cross product of two operators is related to the dot product through the vector triple product. It can be calculated using the formula A x B = A * B * sin(theta), where A and B are the two operators and theta is the angle between them. This relationship shows that the dot product and cross product are not independent of each other.

Similar threads

Replies
21
Views
2K
  • Quantum Physics
Replies
9
Views
1K
Replies
11
Views
1K
  • Quantum Physics
Replies
13
Views
1K
  • Quantum Physics
Replies
2
Views
951
Replies
10
Views
1K
  • Quantum Physics
Replies
7
Views
1K
Replies
1
Views
1K
  • Quantum Physics
Replies
15
Views
2K
  • Quantum Physics
Replies
3
Views
912
Back
Top