Calculating Acceleration: Understanding Horizontal Forces on a 3kg Mass

  • Thread starter RadiationX
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In summary, a 3kg mass is being acted upon by two horizontal forces: 9.0 N due east and 8.0 N at 62 degrees north of west. The magnitude of the body's acceleration is 2.9 m/s^2. However, the solution in the book is 1.74808 m/s^2, which is missing the northward component of the second force. The book's answer is correct and can be found by using trigonometry to add the two force vectors.
  • #1
RadiationX
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only two horozontal forces act on a 3kg mass. one force is 9.0 N acting due east, and the other is 8.0 N acting 62 degrees north of west. what is the magintude of the body's acceleration.


The answer in the book is 2.9 m/s^2. but how can this be?

shouldn't the solution be (9 + 8cos(118))/3 = 1.74808 m/s^2 ?
 
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  • #2
you are missing a component of the force

Sure you got that first part right but you're missing the fact that there is ANOTHER COMPONENT of force being appleid on this object. You decomposed that 8N force in 8cos 62 and 8sin62 what hapopened to the 8sin62?
 
  • #3
What about the northward component of the second force?

The book's answer is correct.
 
  • #4
damn is all i can say
 
  • #5
You can deal with x and y components separately as you did, or you can use trigonometry to add the two force vectors.
 
  • #6
"i can't be this dumb. can i? "

Don't ask questions like that! You might not like the answers!
 

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