- #1
missrikku
I have been having trouble getting key components of this problem:
A plan is flying in a horizontal circle at a speed of 480 km/h. The wings are tilted 40 degrees to the horizontal. What is the radius of the circle in which the plane is flying? Assume that the required force is provided entirely by an "aerodynamic lift" that is perpendicular to the wing surface.
okay, so I have:
V = 480 km/h
@ = 40 deg
Find: R
That required force would look much like the Normal force of a box on an incline plane, right?
So, could i use:
Fy = N - mgcos@ = ma ?
with a = V^2/R
but, I don't have a mass to use. So I'm unsure as how to approach this. Would I also need to find Fx?
Fx = mgcos@ = ma, right?
A plan is flying in a horizontal circle at a speed of 480 km/h. The wings are tilted 40 degrees to the horizontal. What is the radius of the circle in which the plane is flying? Assume that the required force is provided entirely by an "aerodynamic lift" that is perpendicular to the wing surface.
okay, so I have:
V = 480 km/h
@ = 40 deg
Find: R
That required force would look much like the Normal force of a box on an incline plane, right?
So, could i use:
Fy = N - mgcos@ = ma ?
with a = V^2/R
but, I don't have a mass to use. So I'm unsure as how to approach this. Would I also need to find Fx?
Fx = mgcos@ = ma, right?