- #1
broegger
- 257
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I have a somewhat simple question, that I for some reason can't figure out..
suppose you have a circuit with a source of emf (e.g. a battery).. if you put a single resistor in this circuit there is a potential drop equal in size to the emf (i neglect internal resistance in the source).. now, if you place a second, identical resistor in the circuit the potential drop over the first resistor will be exactly half of it's initial value (that is, 1/2*emf).. my question is: how does the electrons "know" only to put half their energy in the first resistor and save the other half for the second - how does they detect the presence of the new resistor?
I'm sure I should know this, but my book doesn't offer any explanation..
suppose you have a circuit with a source of emf (e.g. a battery).. if you put a single resistor in this circuit there is a potential drop equal in size to the emf (i neglect internal resistance in the source).. now, if you place a second, identical resistor in the circuit the potential drop over the first resistor will be exactly half of it's initial value (that is, 1/2*emf).. my question is: how does the electrons "know" only to put half their energy in the first resistor and save the other half for the second - how does they detect the presence of the new resistor?
I'm sure I should know this, but my book doesn't offer any explanation..