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I'm working on choosing an appropriate motor. I have the calculations I need for the required torque, power, max velocity, force, and acceleration. Now I need to know the maximum velocity that a specific motor can move 159 kg 0.45 m across a horizontal plane.
In all of my calculations for which motor was needed, I neglected to take friction and inertia into consideration because I did not need to be so exact. The friction is quite minimal anyway. It is a seat moving along a metal rail.
The motor specs are as follows:
Torque - 0.304 Nm
Speed - 4000 RPM
Power - 0.13 kW
Gearing - 60:1 (15*4)
Inertia - .031 kg-cm^2
I don't yet know what the radius of the gear attached to the gearbox will be. I imagine something like 5 cm. I was told that the equation would involve something like (2pi*r(RPM))/15, but I don't know how that will work in with the power, mass, and distance when calculating the max velocity.
I was thinking if using 1/2*130*0.45 would be possible to use for the kinetic energy and then solve for v with 29.25=1/2*159*v^2. But again, I'm not sure how to work in the Speed and gearing of the motor.
I appreciate the help. If I'm missing any info, let me know.
In all of my calculations for which motor was needed, I neglected to take friction and inertia into consideration because I did not need to be so exact. The friction is quite minimal anyway. It is a seat moving along a metal rail.
The motor specs are as follows:
Torque - 0.304 Nm
Speed - 4000 RPM
Power - 0.13 kW
Gearing - 60:1 (15*4)
Inertia - .031 kg-cm^2
I don't yet know what the radius of the gear attached to the gearbox will be. I imagine something like 5 cm. I was told that the equation would involve something like (2pi*r(RPM))/15, but I don't know how that will work in with the power, mass, and distance when calculating the max velocity.
I was thinking if using 1/2*130*0.45 would be possible to use for the kinetic energy and then solve for v with 29.25=1/2*159*v^2. But again, I'm not sure how to work in the Speed and gearing of the motor.
I appreciate the help. If I'm missing any info, let me know.
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