## [Javascript?] Using a function as an argument for another function

Code:
var square = function (x) {
return x * x;
};

var cube = function (x) {
return square * x;
};
This is my shot, its not right. Please indicate or suggest the correct answear. :)
 PhysOrg.com science news on PhysOrg.com >> King Richard III found in 'untidy lozenge-shaped grave'>> Google Drive sports new view and scan enhancements>> Researcher admits mistakes in stem cell study

Mentor
 Quote by mindauggas Code: var square = function (x) { return x * x; }; var cube = function (x) { return square * x; }; This is my shot, its not right. Please indicate or suggest the correct answear. :)
No, it's not correct.
Code:
var cube = function (x) {
return x * square(x);
};
Your thread title is misleading - you aren't using a function as an argument of another function. One function is calling another function. There's a difference.
 Recognitions: Homework Help In C or C++, you can use pointers to functions as arguments: Code: #include int f1xf2(int (*pf1)(int), int (*pf2)(int), int v){return(pf1(v) * pf2(v));} int returnv(int v){return(v);}; int square(int v){return(f1xf2(returnv, returnv, v));} int cube(int v){return(f1xf2(returnv, square, v));} int quad(int v){return(f1xf2(square, square, v));} int main(int argc, char ** argv) { printf("square 2 = %3d\n", square(2)); printf("cube 3 = %3d\n", cube(3)); printf("quad 4 = %3d\n", quad(4)); return(0); }

## [Javascript?] Using a function as an argument for another function

I am confused...it always bugs me when people do not state what language they are talking about...sure, if I knew, I would recognize it; but often times I don't and I can still help, if I knew what to google.

So, the last post is C, sure...what's the first one, too? or is it matlab?
 Mentor Looks like JavaScript to me.
 Sorry, it's JavaScript
 Once again, sorry. This time for abandoning my own topic. Like I said the programming language is JavaScript. And yes, thanks for pointing out, that the title is misleading: the function is indeed calling another function, not using it as an argument. Returning to the problem. "When we call the square function as a part of the cube function, we still have to define the parameter associated with the square function" - a hint provided says thus. But how to write this assignment? I have never assigned a parameter for a function in the body of another function. Any hints? Should I assign a parameter the same way as a variable?
 These kind of simple questions is something you don't need a forum for...you can play around with the language and its compiler/interpreter and test stuff at will...it does not cost any money and you are not going to break anything...play around, experiment! ...if, on the other hand, you have a major logic problem or a bug that you cannot find...then, the forum could help.

Recognitions:
Homework Help
 Quote by mindauggas Returning to the problem. "When we call the square function as a part of the cube function, we still have to define the parameter associated with the square function" - a hint provided says thus. But how to write this assignment? I have never assigned a parameter for a function in the body of another function. Any hints? Should I assign a parameter the same way as a variable?
Can you state the original problem/assignment as it is given to you?
 Recognitions: Gold Member Using a function as an argument to another function would work like this: Code: var square = function(x) { return x * x; } var cube = function(f,x) { return x * f(x); } cube(square,2); Though in this context I don't know why you'd want to pass in a function. I don't imagine you'd ever be swapping it out.

 Quote by DavidSnider Using a function as an argument to another function would work like this: Code: var square = function(x) { return x * x; } var cube = function(f,x) { return x * f(x); } cube(square,2); Though in this context I don't know why you'd want to pass in a function. I don't imagine you'd ever be swapping it out.
Thanks, this solved it.

Code:
var square = function (x) {
return x * x;
};

var cube = function (x) {
return square(x) * x;
};
The answer to your question: it just for the sake of knowing how to use functions in all/allmost alt the ways legitimate.
 Recognitions: Homework Help I thought the idea was to use functions as parameters to other functions. I'm not sure if this syntax is correct for javascript, but it should look something like this: Code: var f1xf2 = function(f1, f2, x) {return f1(x) * f2(x);} var returnx = function(x) {return x;} var square = function(x) {return x * x;} var cube = function(x) {return f1xf2(returnx, square, x);}

 Quote by rcgldr I thought the idea was to use functions as parameters to other functions. I'm not sure if this syntax is correct for javascript, but it should look something like this: Code: var f1xf2 = function(f1, f2, x) {return f1(x) * f2(x);} var returnx = function(x) {return x;} var square = function(x) {return x * x;} var cube = function(x) {return f1xf2(returnx, square, x);}
The original title probably mislead you, I apologize for this. the title should have stated that one function calls another function :)