- #1
nrc_8706
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In one cycle, a heat engine absorbs 520J from the high-tempt reservoir and expels 390J to a low-tempt. reservoir. If the efficiency of this engine is 68% of the efficiency of a Carnot engine, what is the ratio of the low tempt. to the high tempt. in the Carnot engine?
e=1-(390/520)=.25 Carnot engine
e=.68*.25=.17 e=.25+.17=.42
.42=1-(Tl/Th)
Tl/Th=1-.42=.58
Is this correct?
e=1-(390/520)=.25 Carnot engine
e=.68*.25=.17 e=.25+.17=.42
.42=1-(Tl/Th)
Tl/Th=1-.42=.58
Is this correct?