Non-homogeneous 2nd order diff eq involves power series

In summary, to find a power series solution about x=0 for the non-homogenous equation y'' + xy' + y = x^2 +2x +1, substitute y = \sum_{n=0}^{\infty}a_nx^{n} and equate coefficients to find a_n, n = 2,3,4,5 using the Frobenius method. The solution will be in the form of y=a_0 y_1 + a_1 y_2 + y_p, where a_0 and a_1 are arbitrary constants and the first three nonzero terms of each of the three series y_1,y_2, and y_p will need to be determined.
  • #1
diffeqnoob
14
0
I just need a hint or something to see where I start. I'm at a loss for a beginning.

Consider the non-homogenous equation
[tex]y'' + xy' + y = x^2 +2x +1[/tex]

Find the power series solution about [tex]x=0[/tex] of the equation and express your answer in the form:

[tex]y=a_0 y_1 + a_1 y_2 + y_p[/tex]

where [tex]a_0[/tex] and [tex]a_1[/tex] are arbitrary constants. Give only the first three nonzero terms of each of the three series[tex]y_1[/tex],[tex]y_2[/tex], and [tex]y_p[/tex]

Hint: Substitute [tex] y = \sum_{n=0}^{\infty}a_nx^{n}[/tex] and equate coefficients to find [tex]a_n[/tex], [tex]n = 2,3,4,5[/tex]
 
Physics news on Phys.org
  • #2
Do you know how to take the derivative of y in that form? If so, plug it in, and then try to rearrange the expression so that you have an infinite linear combination of powers of x that is equal to 0. Since the powers of x are linearly independent, all these coefficients must equal to zero, which will give you an expression for a_n in terms of a_n-1 and maybe a_n-2. This is called the Frobenius method, if you want to look online for a better explanation.
 

1. How do you solve a non-homogeneous 2nd order differential equation involving power series?

To solve a non-homogeneous 2nd order differential equation involving power series, you can use the method of undetermined coefficients. This involves finding a particular solution that satisfies the non-homogeneous term and adding it to the general solution of the corresponding homogeneous equation.

2. What is the general form of a non-homogeneous 2nd order differential equation involving power series?

The general form of a non-homogeneous 2nd order differential equation involving power series is y'' + P(x)y' + Q(x)y = R(x), where P(x) and Q(x) are functions of x and R(x) is the non-homogeneous term.

3. What are the initial conditions for solving a non-homogeneous 2nd order differential equation involving power series?

The initial conditions for solving a non-homogeneous 2nd order differential equation involving power series are typically given as the values of y and y' at a specific point. These conditions are used to determine the constants in the general solution of the homogeneous equation.

4. Can a non-homogeneous 2nd order differential equation involving power series have multiple solutions?

Yes, a non-homogeneous 2nd order differential equation involving power series can have multiple solutions. This is because the particular solution may not be unique, and there may be an infinite number of solutions if the non-homogeneous term is a linear combination of the general solution for the corresponding homogeneous equation.

5. What are some applications of solving non-homogeneous 2nd order differential equations involving power series?

Solving non-homogeneous 2nd order differential equations involving power series is important in many areas of science and engineering, such as physics, chemistry, and electrical engineering. These equations can be used to model a wide range of phenomena, from the growth of populations to the behavior of electrical circuits.

Similar threads

  • Calculus and Beyond Homework Help
Replies
2
Views
275
Replies
8
Views
990
  • Calculus and Beyond Homework Help
Replies
8
Views
1K
  • Calculus and Beyond Homework Help
Replies
11
Views
2K
  • Calculus and Beyond Homework Help
Replies
9
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
933
Replies
13
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
968
  • Calculus and Beyond Homework Help
Replies
9
Views
1K
  • Calculus and Beyond Homework Help
Replies
6
Views
1K
Back
Top