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colsandurz45
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I have this problem for class and I'm kind of stuck on all of them. Any help would be appreciated.
a stone of weight w is thrown vertically with initial speed v0. air drag force dissipates at a rate of f*y of mechanical energy as the stone travels distance y.
a) show that the maximum height of the stone is
h = (v0)^2/(2g(1+f/w))
b) show that the speed of the stone upon impact is
v = v0*((w-f)/(w+f))^(1/2)
thanks in advance
a stone of weight w is thrown vertically with initial speed v0. air drag force dissipates at a rate of f*y of mechanical energy as the stone travels distance y.
a) show that the maximum height of the stone is
h = (v0)^2/(2g(1+f/w))
b) show that the speed of the stone upon impact is
v = v0*((w-f)/(w+f))^(1/2)
thanks in advance
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