- #1
Skynt
- 39
- 1
It should be really simple, but I think the algebra is bogging me down:
[tex]\frac{n!}{(n-i)! i!} + \frac{n!}{[n-(i+1)]! (i+1)!} = \frac{(n+1)!}{(n-i)! (i+1)!}[/tex]
Can anyone show me the process of proving this? I don't see how the two expressions are equal...
essentially I can't get rid of the [n - (i + 1)]! term when I try to combine the two fractions and expand things.
[tex]\frac{n!}{(n-i)! i!} + \frac{n!}{[n-(i+1)]! (i+1)!} = \frac{(n+1)!}{(n-i)! (i+1)!}[/tex]
Can anyone show me the process of proving this? I don't see how the two expressions are equal...
essentially I can't get rid of the [n - (i + 1)]! term when I try to combine the two fractions and expand things.
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