Wave function of Stationary State

In summary, the conversation discusses the concept of a particle having a definite energy and how it relates to the probability density and uncertainty principle. The participants also question the existence of a particle with a definite momentum and the limitations of the one-particle Schrodinger equation. The conversation concludes that these are merely toy examples and do not fully represent reality.
  • #1
I_am_learning
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I learned (University Physics, 9th Edition, Extended Version) that the wave function of a particle having a definite energy is independent of time. This means the probability Density of the particle don't change with time, i.e. If a particle is 90% likely to be found some where now, There is always 90% chance of finding the particle at the same place.

What I am confused on is in this Scenario---
Suppose a particle is moving in freely in free space with certain constant velocity therefore having constant Energy.
Then How is it possible that the particle is always most likely to be found at its starting position.?
My institution Tells me that the probability density should constantly change with time as the particle moves.
 
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  • #2
A particle in free space that has a definite energy, and for a free particle that also means a precisely defined momentum, that is [tex]\Delta p = 0[/tex]. So the uncertainty principle tells us that uncertainty in position must be infinite; the particle cannot be specifically located, so it has the same probability of being located anywhere.
 
  • #3
You said it yourself: Definite velocity (momentum) and a starting position...

What starting position?

If you have a certain velocity you don't have a starting position because you could be anywhere.

You cannot assume a starting position as well as a definite energy. If your particle is in a "starting position", then we would have to argue that the electron must somehow be localized, but then you wouldn't have a pure momentum state.
 
  • #4
kanato said:
A particle in free space that has a definite energy, and for a free particle that also means a precisely defined momentum, that is [tex]\Delta p = 0[/tex]. So the uncertainty principle tells us that uncertainty in position must be infinite; the particle cannot be specifically located, so it has the same probability of being located anywhere.

I quite got where I was slipping. But one question still remains.
For an electron revolving round the nucleus in stationary state, It can't be true that the uncertainty in position is infinite. We at least Know that the electron is somewhere around the nucleus, It obviously can't be in the another corner of the solar system.
 
  • #5
thecritic said:
I quite got where I was slipping. But one question still remains.
For an electron revolving round the nucleus in stationary state, It can't be true that the uncertainty in position is infinite. We at least Know that the electron is somewhere around the nucleus, It obviously can't be in the another corner of the solar system.

By making similar arguments, it can't be true that the electron is revolving with a "pure" momentum state. Because the levels are always "broadened", they are not "real" discrete states (delta functions).

Remember all these are really toy examples, and do not faithfully represent reality.
 
  • #6
sokrates said:
By making similar arguments, it can't be true that the electron is revolving with a "pure" momentum state. Because the levels are always "broadened", they are not "real" discrete states (delta functions).
Remember all these are really toy examples, and do not faithfully represent reality.
The electrons are in stationary State, Thats for sure, Right?
Then The wave function is time independent, Right?
And don't this means that there is the equal probability of finding the electron anywhere?
 
  • #7
thecritic said:
I learned (University Physics, 9th Edition, Extended Version) that the wave function of a particle having a definite energy is independent of time. This means the probability Density of the particle don't change with time, i.e. If a particle is 90% likely to be found some where now, There is always 90% chance of finding the particle at the same place.
Are you sure about what you imply?
To me it seems that "the wave function of a particle having a definite energy is independent of time" means that sum of potential energy and kinetic energy is independent of time while separately potential energy and kinetic energy can vary with time.
 
  • #8
I think the most basic objection to an argument that involved a free particle of definite momentum is that a free particle with definite momentum simply DOES NOT EXIST. The stationary states (definite momentum) of a free particle are not normalizable and hence, are unphysical.
 
  • #9
nnnm4 said:
I think the most basic objection to an argument that involved a free particle of definite momentum is that a free particle with definite momentum simply DOES NOT EXIST. The stationary states (definite momentum) of a free particle are not normalizable and hence, are unphysical.
A side question.
Does it mean that free particle (photon) with definite velocity does not exist?
 
  • #10
I think what the original poster is asking in another way is,

If you have a particle in an infinite space with no potential, and perform an energy measurement of that particle, do you not collapse the wavefunction into a single energy eigenstate which is time-independent?

Is the solution that the energy of the particle gives you no information about the position or momentum?

Also, I am not certain if the problem is well-defined- how can you normalise a wavefunction which is defined over an infinite space, and by symmetry, transnationally invariant? (but non-zero!)
 
  • #11
thecritic said:
The electrons are in stationary State, Thats for sure, Right?

No, that's not right.

An electron in an excited state will relax, right? If the excited level was really a stationary state, then there would be no relaxation to the ground state. An excited electron would stay in that energy forever.

One-particle Schrodinger equation does not capture this, there's always a slight broadening in the levels.

These are toy examples. Don't take them seriously. Or study many-body perturbation theory.
 
  • #12
zonde said:
A side question.
Does it mean that free particle (photon) with definite velocity does not exist?

Not at all... It just means that because you know the velocity exactly

you have lost all the information regarding the position. Exact frequencies are both theoretically and experimentally possible (,say, for a free electron in vacuum) - it is the coupling to the environment that corrupts pure states. This "environment effect" is usually much more stronger. It "broadens" the energy levels and introduces effects like relaxation etc..
 
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  • #13
thecritic said:
I quite got where I was slipping. But one question still remains.
For an electron revolving round the nucleus in stationary state, It can't be true that the uncertainty in position is infinite. We at least Know that the electron is somewhere around the nucleus, It obviously can't be in the another corner of the solar system.

The case of the the electron orbitting a nucleus is different from the free particle case. The reason is that in this case a definite energy state does not correspond to a definite momentum state (in the case of a free particle it does). So it is in fact possible for the particle to sit in a stationary state (an energy eigenstate). And in this state there is both an uncertainty in the position and the momentum (but it doesn't stretch out to infinity).

sokrates said:
No, that's not right.

An electron in an excited state will relax, right? If the excited level was really a stationary state, then there would be no relaxation to the ground state. An excited electron would stay in that energy forever.

One-particle Schrodinger equation does not capture this, there's always a slight broadening in the levels.

These are toy examples. Don't take them seriously. Or study many-body perturbation theory.
The relaxation process is a different process. For that to take place you need some way to divert the energy away from the nucleus/electron system. For that to take place you need some sort of interaction process. In fact, what happens is that the electron interacts with the QED vacuum -- in some sense a virtual photon can kick the electron to a lower energy state. As a result the electron emits a photon.

But strictly speaking, in the absence of interactions quantum mechanics does not predict any relaxation and the energy eigenstates become truly stationary. But you are right that this is just a toy model.
 
  • #14
thecritic said:
The electrons are in stationary State, Thats for sure, Right?
Then The wave function is time independent, Right?
And don't this means that there is the equal probability of finding the electron anywhere?

NO,the equal proabability of finding the electron anywhere means the electron is in a momentum eigenstate.However an electron revolving round the nucleus is effected by a potential,so its momentum doesn't commute with the Hamiltonnian.That means although the electron is just in stationary state,it's not in a momentum eigenstate.
 
  • #15
xepma said:
The relaxation process is a different process. For that to take place you need some way to divert the energy away from the nucleus/electron system. For that to take place you need some sort of interaction process. In fact, what happens is that the electron interacts with the QED vacuum -- in some sense a virtual photon can kick the electron to a lower energy state. As a result the electron emits a photon.

But strictly speaking, in the absence of interactions quantum mechanics does not predict any relaxation and the energy eigenstates become truly stationary. But you are right that this is just a toy model.

What do you mean the relaxation process is different? After interacting with the vacuum, electron still -relaxes- right? I'd still call it "relaxation" even if the excited atom falls back on a lower sate in vacuum.

Relaxation is pretty loose terminology so I couldn't figure whether you are saying anything different.
 
  • #16
Seems Like I have to do further Drilling into the subject. I quite don't know what's meant by momentum eigenstate
 
  • #17
I think you would be able answer this for me.
Suppose I go into a large vacant space (to get rid of all environment influences). Then I project single electron with an electron gun.
--Do this electron now have a definite velocity/momentum or not?
--What is the wave function of this electron like?
(Since the electron always moves in zero potential region, I guess that its Kinetic Energy (whatever that may be) remains constant. Since the only energy involved is the kinetic Energy, I find it sensible to say that the Total Energy of the electron also remains constant. Then there should be no objection in saying the the electron is in Stationary State, is there? Correct me where I am wrong.)
 

1. What is the wave function of a stationary state?

The wave function of a stationary state is a mathematical representation of the probability amplitude of finding a particle in a particular energy state. It is described by the Schrödinger equation and is a fundamental concept in quantum mechanics.

2. How is the wave function of a stationary state different from a non-stationary state?

A stationary state is a state of definite energy and does not change with time, while a non-stationary state is a combination of different energy states and evolves over time. The wave function of a stationary state is a constant, while the wave function of a non-stationary state changes with time.

3. Is the wave function of a stationary state always a real value?

No, the wave function of a stationary state can be a complex number. In quantum mechanics, complex numbers are used to represent the amplitude and phase of a wave function. The squared magnitude of the wave function gives the probability of finding a particle in a particular energy state.

4. Can the wave function of a stationary state have multiple peaks?

Yes, the wave function of a stationary state can have multiple peaks. This indicates that there are multiple energy states with the same energy level. The number of peaks in the wave function corresponds to the number of degenerate energy levels.

5. How does the wave function of a stationary state change with a perturbation?

If a perturbation is applied to a system in a stationary state, the wave function will change to reflect the new energy levels of the system. The new wave function will have a different shape and may have multiple peaks, depending on the type and magnitude of the perturbation. However, the total probability of finding the particle in any energy state will still be 1.

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