Minimize Tension of Mass m Hanging from Cords

  • Thread starter munchy35
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In summary, the problem involves a package of mass m hanging from a short cord tied to the wall and ceiling. The tension in the second cord is minimized at a value of theta = 0 degrees and the minimum tension in the second cord is 1.192mg. The problem can be solved by using the component method and eliminating t1 to find t2, then minimising t2.
  • #1
munchy35
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Homework Statement



A package of mass m hangs from a short cord that is tied to the wall via cord 1 and to the ceiling via cord 2. Cord 1 is at angle 40 degrees with the horizontal; cord 2 is at angle, theta.

a) for what value of theta is the tension in cord 2 minimized?
b)in terms of mg, what is the minimum tension in cord 2?

(here's the link of the problem with the picture http://www.unc.edu/~rowan/phys26/P26recit/p26-12-b.htm )

I know I have to figure out the force diagram first. I'm just having trouble with where to start.

I'm not asking for the solution, i just need some direction,
 
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  • #2
Hi munchy35! :wink:

You can solve this either with a vector triangle, or by taking components in a convenient direction.

Choose one method, and show us how far you get. :smile:
 
  • #3
i used the component method so

for horizontal component i said t1cos40=t2cosx

(i'm just using x for theta)

t2=t1cos40/cosx

and t1 = t2cosx/cos40

so for part a, i used the t2 equation and just assumed for t2 to be a minimum cos x had to be maximum, the maximum cosx=1, so x= 0 degrees

^ can i just assume that?

for part b, i used vertical component

t1sin40 + t2sinx = mg

after plugging in t1

t2 = mg/ tan40cos0 + sin0

and eventually get 1.192mg

is that right
 
  • #4
Hi munchy35! :smile:
munchy35 said:
… for horizontal component i said t1cos40=t2cosx

t1sin40 + t2sinx = mg

so for part a, i used the t2 equation and just assumed for t2 to be a minimum cos x had to be maximum, the maximum cosx=1, so x= 0 degrees

^ can i just assume that?

Nooo … stop trying to take short-cuts! :rolleyes:

Your two equations are correct :smile:

now eliminate t1 to find t2 …

then minimise t2. :wink:
 

What is the purpose of minimizing tension of a mass hanging from cords?

The purpose of minimizing tension is to prevent the cords from breaking and to ensure that the mass is securely suspended.

What factors affect the tension of the cords?

The tension of the cords is affected by the weight of the mass, the length and elasticity of the cords, and the angle at which the cords are suspended.

How can tension be minimized in this scenario?

Tension can be minimized by using strong and sturdy cords, keeping the length of the cords shorter, and ensuring that the cords are suspended at a 90 degree angle.

What are the consequences of not minimizing tension in this situation?

If tension is not minimized, the cords may break and the mass could fall, causing potential damage or injury.

How can the tension of the cords be calculated?

The tension of the cords can be calculated by using the formula T = mg + ma, where T is the tension, m is the mass, g is the acceleration due to gravity, and a is the angle at which the cords are suspended.

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