Gib Z said:Umm...unless you were meant to get a protractor and measure the angle, you don't have enough information for the problem. Also, the "direction" of the range is to the right. Were you given ANY other information?
Jebus_Chris said:If an object is launched on a flat surface the maximum range comes when the angle is 45.
Keldon7 said:In all fairness, even if it was scaled up the angle would remain identical, similar triangles and such. But, I don't think they're putting emphasis on the picture here, the question is simply "What is the maximum range for a cannon with muzzle velocity 322m/s?". So Jebus_Chris is right.
Jebus_Chris said:If an object is launched on a flat surface the maximum range comes when the angle is 45.
huybinhs said:So It comes out with:
R = (V0^2 * sin2angles)/g
=> R = 10580 m. Is this correct?
The maximum range of a cannon can be calculated using the following formula: R = (V^2 * sin(2θ))/g, where R is the maximum range, V is the muzzle speed, θ is the angle of elevation, and g is the acceleration due to gravity.
The angle of elevation for maximum range can be determined by finding the angle at which the sine function is equal to 1. This angle is known as the optimum angle and is typically around 45 degrees for most cannons.
Yes, increasing the muzzle speed will result in an increase in the maximum range of a cannon. However, this increase may not be significant unless the initial muzzle speed is relatively low.
The maximum range of a cannon can be affected by several factors, including the muzzle speed, angle of elevation, air resistance, wind speed and direction, and the weight and shape of the projectile being fired.
Yes, the maximum range of a cannon can be calculated using different units of measurement, such as feet per second for muzzle speed and feet for distance. However, it is important to ensure that all measurements are converted to the same units before using the formula to calculate the maximum range.