- #1
likephysics
- 636
- 2
I am bit confused about precision rectifier/superdiode circuit using opamp.
The first ckt in the wikipedia link - http://en.wikipedia.org/wiki/Precision_rectifier
When the input is positive, say 1v, the opamp tries to make the -ve terminal equal to its +ve terminal. So to do that, the output has to be 1.6v (1V+diode drop). This part I understand.
Lets say the input is -1v. Now the opamp tries to make the -ve terminal equal to its +ve terminal. To do that the output has to be -1.6V.
But then the output would be -1v. Where am I going wrong?
The first ckt in the wikipedia link - http://en.wikipedia.org/wiki/Precision_rectifier
When the input is positive, say 1v, the opamp tries to make the -ve terminal equal to its +ve terminal. So to do that, the output has to be 1.6v (1V+diode drop). This part I understand.
Lets say the input is -1v. Now the opamp tries to make the -ve terminal equal to its +ve terminal. To do that the output has to be -1.6V.
But then the output would be -1v. Where am I going wrong?