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Crusaderking1
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Question on torque(center of mass being important I think)
I have a lab report due tomorrow, and I have it all done except one calculation, but it confuses me.
The center of mass on my meter stick on a stand is 50.1 cm, or .501 meters.
For part B, we changed the pivot point to 30.0 cm(not the center of mass), or .300 meters. then with 3 mass hanging by a rope are added. I understand that torque is force times radius.
The question is what OTHER forces are acting on the system besides the weights we added on, and then find the torque, mass, radius, and distance.
I suppose this is referring to the force of gravity *mass of meter stick with the distance being .501 - .300 = .201 meters. The torque would then be .164675 Nm. Is this right?
Please help. Thanks.
sine = 1
radius * force = torque
Homework Statement
I have a lab report due tomorrow, and I have it all done except one calculation, but it confuses me.
The center of mass on my meter stick on a stand is 50.1 cm, or .501 meters.
For part B, we changed the pivot point to 30.0 cm(not the center of mass), or .300 meters. then with 3 mass hanging by a rope are added. I understand that torque is force times radius.
The question is what OTHER forces are acting on the system besides the weights we added on, and then find the torque, mass, radius, and distance.
I suppose this is referring to the force of gravity *mass of meter stick with the distance being .501 - .300 = .201 meters. The torque would then be .164675 Nm. Is this right?
Please help. Thanks.
Homework Equations
sine = 1
radius * force = torque
The Attempt at a Solution
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