Solving Linear Geometry for a 'projected intersection'

In summary, the conversation discusses finding a projected intersection between two line segments in 3D using a ray that is perpendicular to an axis and passes through both segments. The speaker suggests using an optimization approach to minimize the distance between the segments and the ray. They also mention using a norm equation and restrictions on the parameterization of the segments to solve for the intersection point. The speaker asks if this is the best or simplest method and inquires about the listener's experience with optimization.
  • #1
athuss
5
0
Working on another problem here with varying results. I have three line segments in 3D and am looking to find what would be a projected intersection between two. This projected intersection is defined by a ray that is perpendicular to the axis a and passes through both segments f and s.

f and s do not necessarily intersect, nor do either f and s with a. But there are occasions where the ray satisfies the perpendicular to the axis requirement, as well as passes through both f and s.

The ray does not need to be perpendicular to f and s.

I've gotten to a point where I have three linear equations with respect to line parameters t,u and v. But I haven't been able to correctly solve for the three values using Guassian Elimination.

Just wondering if this is the best (or even correct) way to go about it or is there an easier (simpler?) method.

Thanks the for help.
 

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  • #2
Hey athuss and welcome to the forums.

One suggestion I have is that since f and s don't necessarily intersect, what you could do is turn this into an optimization problem where give a parameterization of both f and s for some parameter t and u (for f and s respectively) and maintaining that you have boundaries for the t and u variables (since they are rays and not lines), you find the situation where ||f-s|| is minimized.

If you get a zero distance, then it means that they intersect but otherwise, you get the point of intersection at the perpendicular distance because in normal cartesian geometry, things are minimized when they are perpendicular to one another.

Once you have this then you do another minimization problem to find the minimal distance between the point you obtained above, and the line segment corresponding to the vector a (you can also treat a as a ray by restriction the domain of the parameterization). The idea behind this is that the minimal distance corresponds to a perpendicular distance.

So once you have the point on a and the point for (f,s) rays (even if they don't intersect), then you have all the information required.

In terms of how to do the optimization, use the norm equation to be ||f-s||^2 = <f-s,f-s> and take it from there (where you have f and s in terms of t and u and some restriction on t and u).

Have you done optimization before at any level?
 

1. What exactly is "projected intersection" in linear geometry?

"Projected intersection" refers to the point where two or more lines or shapes intersect when they are projected onto a 2D plane. This is commonly used in engineering and architecture to determine the intersection of building elements or in computer graphics to create perspective drawings.

2. How do you solve for projected intersection in linear geometry?

To solve for projected intersection, you can use algebraic methods such as substitution or elimination to find the coordinates of the intersection point. Alternatively, you can use geometric constructions or trigonometric methods to determine the intersection point.

3. What types of problems can be solved using projected intersection in linear geometry?

Projected intersection can be used to solve a variety of problems, including finding the intersection of lines, determining the intersection of planes in 3D space, and calculating the intersection of curves or surfaces. It is also commonly used in applications such as computer graphics, engineering, and architecture.

4. How does the number of dimensions affect solving for projected intersection in linear geometry?

The number of dimensions does not significantly impact the process of solving for projected intersection in linear geometry. Whether the problem is in 2D or 3D, the same mathematical principles and methods can be applied to determine the intersection point.

5. What are some real-life applications of solving for projected intersection in linear geometry?

Projected intersection is used in many fields, including architecture, engineering, computer graphics, and surveying. It is used to calculate the intersection of building elements such as walls, beams, and pipes, to create perspective drawings, and to determine the location of underground utilities. It is also commonly used in GPS navigation systems to determine the intersection of roads or paths.

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