Someone with a math computer program

[msmith12]

so, this is probably not exactly posted in the right place, but I was wondering if someone could enter a couple of things into a math program for me. I have two simple systems of equations and need the values for them, and unfortunately, don't have mathematica on this computer, and I reallly don't want to try these out with pencil and paper... so without further adiou...

$$(1-a-b)(1+4x+3y)=a(4-4x-y)=b(2+y)$$
$$(1-x-y)(1+6a-b)=x(4-2a+8b)=y(6-5a-6b)$$

and...

$$a(1+4x+3y)=b(4-4x-y)$$
$$x(4a+2b)=y(6a+b)=(1-x-y)(a+7b)$$

i need to find the values of a,b,x,y for each set of equations.

(in case you were wondering where these came from, they are the equilibrium probabilites that player A chooses 1,2,3 and player B chooses a,b,c)

thanks a bunch

~tired of number crunching

 

[Manchot]

It appears that your equations are overdetermined. You only have 4 unknowns, but you have 7 equations, which either means that 3 of them are redundant, or there is no solution. I don't have a math program either, so I can't verify that statement.

BTW, this really belongs more in the Linear Algebra forum.

 

[houserichichi]

I checked with Mathematica and the solution set is empty.