- #1
KiwiKid
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Homework Statement
Solve 2cos(x)^2 + 3cos(x) + 1 = 0 for 0 <= x <= 2pi
Homework Equations
Trigonometric equations, yadda yadda yadda.
The Attempt at a Solution
2cos(x)^2 + 3cos(x) + 1 = 0
cos(x)(2cos(x) + 3) = -1
cos(x) = -1/(2cos(x) + 3)
I then figured out that you get a solution when cos(x) = -1 (so x = pi). However, there are supposed to be multiple solutions, and I don't know how to find these. Any pointers?