How do photons split into electrons and positrons?

In summary, the confusion about how photons can split into electrons and positrons is due to the fact that photons do not have mass but do have momentum. This is explained by Special Relativistic equations and can be measured through the force of light on a surface. However, for pair production to occur, another particle must be present to contribute momentum.
  • #1
DuckAmuck
236
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I'm confused about how photons are able to split into electrons and positrons. Learning about four dimensional vectors, but it's still not clear how this happens.
The photon will have a vector of P=(E,p), where p^2=E^2, so P^2=0, since photons don't have mass.
It must be that P = P1 + P2, where P1 and P2 are electron and positron.
P1 = (E1,p1), where E1^2 = p1^2 + m^2.
So (E,p) = (E1,p1) + (E2, p2) = (E1+E2,p1+p2)
So (E,p)^2 = 0 = m^2 + m^2 + E1*E2 - p1*p2
So is the product of p1 and p2 really equal to m^2 + m^2 + E1*E2?!
That would suggest that either p1 or p2 is greater than it's corresponding energy, which would make mass negative.
What am I missing?
 
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  • #2
Photons don't have mass, but they DO have momentum! ;) This is sneaky, but it comes from Special Relativistic equations. In fact, this is measurable, if you shine a light on a surface, the light will actually apply a force on that surface! F=dp/dt

check out some of these formulas:
http://en.wikipedia.org/wiki/Photon#Physical_properties

The equation for relativistic momentum is
[URL]http://upload.wikimedia.org/math/d/2/d/d2dec44ba56c41a31b4d334b144b51d6.png[/URL]
where
[URL]http://upload.wikimedia.org/math/9/c/3/9c3f2777ac6cb5f4c9c1edc647c68311.png[/URL]

If v=c, such is the case for a photon, the gamma term goes to infinity, and when multiplied with zero, well, the result is not easily determinable, but it often equals a real number, such as is the case here with photons.
 
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  • #3
You are missing that for pair production to occur, another particle (usually an atomic nucleus) must be nearby to contribute momentum. Pair production does not occur in vacuum.
 
  • #4
Yup. Four-momentum is not conserved in photon->electron+positron. You need another body to pick up the difference.
 
  • #5
nicklaus and K^2 are correct. See: http://en.wikipedia.org/wiki/Pair_production for a brief introduction. Note that it is possible for two photons to produce a pair in the absence of a massive particle. This is the reverse of anhillation.
 

What is a photon?

A photon is a fundamental particle of light that carries electromagnetic energy and has zero mass and spin.

How can a photon turn into an electron and a positron?

A photon can undergo a process called pair production, where it interacts with a nucleus or another photon, producing an electron and a positron. This process requires a minimum energy of 1.02 MeV.

What is the significance of "photon to electron + positron" in particle physics?

The process of photon to electron + positron is one of the ways in which energy can be converted into matter, which is a fundamental concept in particle physics. It also plays a crucial role in understanding the behavior of particles in high-energy collisions.

Can this process occur naturally?

Yes, this process occurs naturally in high-energy environments such as near stars, in cosmic rays, and in particle accelerators like the Large Hadron Collider.

What are the applications of "photon to electron + positron" conversion?

One of the applications of this process is in medical imaging, where positron emission tomography (PET) scans use positrons produced through pair production to create images of internal organs and tissues. It is also used in particle accelerators for research in nuclear physics and high-energy physics.

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