Transistor not gate function

[tmiddlet]

Transistor "not gate" function

I've been trying to understand the following circuit:

I'm new to circuitry and electrical engineering, so I've had some trouble understanding the function of transistor Q3 and diode D2, I believe the circuit should function without them. If anybody could describe to me their function, that would be great, I under stand the rest.

Thanks!

 

[dlgoff]

I don't understand the 0 V arrow pointing to V_cc as when the switch is grounded, the input would be 0 V but not V_cc which is 5 volts.

Anyway, when the switch/input is at 5volts, Q₂ will saturate and its collector voltage will be low causing Q₃ to not saturate also the emitter voltage of Q₂ will be high causing Q₄ to saturate, so the output would be low (saturation collector to emitter= ~0.2V). Hence the inverter; input high=5V, output low=0.2V.

Now when the switch/input is at 0volts, Q₂ will not saturate and its collector voltage will be high causing Q₃ to saturate also the emitter voltage of Q₂ will be low causing Q₄ to not saturate, so the output will be high (V_cc -saturation collector to emitter=~4.8V). Hence the inverter; input low=0V, output high=4.8V.

And I believe the diode, D₂ is there to prevent whatever is connected to the output not to back feed current into your circuit. But I may be wrong on this point.

Hope this helps

 

[tmiddlet]

The 0 volt arrows just indicate a zero volt difference, so the diode doesn't activate.

Because Q3 and D2 don't seem to significantly change the output voltage, I think you're probably right, they're probably protecting the circuit from back feed current.

They were confusing because they don't seem to affect the behavior of the circuit significantly.

 

[dlgoff]

The 0 volt arrows just indicate a zero volt difference, so the diode doesn't activate.

Because Q3 and D2 don't seem to significantly change the output voltage, I think you're probably right, they're probably protecting the circuit from back feed current.

They were confusing because they don't seem to affect the behavior of the circuit significantly.

Well here's an explanation of what's happening and why the transistors of this circuit

To solve the problem with the high output resistance of the simple output stage the second schematic adds to this a "totem-pole" ("push–pull") output. It consists of the two n-p-n transistors V3 and V4, the "lifting" diode V5 and the current-limiting resistor R3 (see the figure on the right). It is driven by applying the same current steering idea.[12]

When V2 is "off", V4 is "off" as well and V3 operates in active region as a voltage follower producing high output voltage (logical "1"). When V2 is "on", it activates V4, driving low voltage (logical "0") to the output. V2 and V4 collector–emitter junctions connect V4 base–emitter junction in parallel to the series-connected V3 base–emitter and V5 anode–cathode junctions. V3 base current is deprived; the transistor turns "off" and it does not impact on the output. In the middle of the transition, the resistor R3 limits the current flowing directly through the series connected transistor V3, diode V5 and transistor V4 that all are conducting. It also limits the output current in the case of output logical "1" and short connection to the ground. The strength of the gate may be increased without proportionally affecting the power consumption by removing the pull-up and pull-down resistors from the output stage.[16][17]

http://en.wikipedia.org/wiki/Transistor–transistor_logic#TTL_with_a_.22totem-pole.22_output_stage"

 

[tmiddlet]

Thanks for the link, that was a good description, the only part I don't understand is:

The resistor R3 does not increase the output resistance since it is connected in the V3 collector and its influence is compensated by the negative feedback

I don't see why R3 doesn't increase the output resistance

 

[dlgoff]

Thanks for the link, that was a good description, the only part I don't understand is:


I don't see why R3 doesn't increase the output resistance

...transistor V3 operating in active region as a voltage follower...

The key words here are "voltage follower".

Other unity gain buffer amplifiers include the bipolar junction transistor in common-collector configuration (called an emitter follower because the emitter voltage follows the base voltage, or a voltage follower because the output voltage follows the input voltage)...

Bold emphasis by me.

http://en.wikipedia.org/wiki/Voltage_follower#Single-transistor_circuits"

 

[sophiecentaur]

It's been a while since I was doing this stuff but I can't see why is there no 'pull down' resistor somewhere in the base circuit of Q2?
Any ideas?

 

[dlgoff]

It's been a while since I was doing this stuff but I can't see why is there no 'pull down' resistor somewhere in the base circuit of Q2?
Any ideas?

In the circuit note that "Q₁" is a transistor like in this circuit,

It's from this site where the OP, I'm guessing, got the circuit.

http://www.allaboutcircuits.com/vol_4/chpt_3/2.html"
Here, the base charge of Q₂ gets dissipated by the collector of Q₁, when the input goes low, causing Q₂ to cut-off. Then when the input goes high, current is steered to the base of Q₂, causing it to saturate. So there is no need for a pull-down resistor.