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JPOconnell
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Homework Statement
Two very large open tanks A and F (the figure (Figure 1) ) contain the same liquid. A horizontal pipe BCD, having a constriction at C and open to the air at D, leads out of the bottom of tank A, and a vertical pipe E opens into the constriction at C and dips into the liquid in tank F. Assume streamline flow and no viscosity.
If the cross-sectional area at C is one-half the area at D and if D is a distance below the level of the liquid in A, to what height will liquid rise in pipe E? (in ration of (h2/h1), or just an equation for h1 in h2 is fine)
Link to picture:
Homework Equations
d here is density of the fluid, in this case it is constant.
Bernoulli's equation: p1 + dgy1 + (1/2)(dv1)2 = p2 + dgy2 + (1/2)d(v2)2
Density = Av (A is the area of flow surface, while v is the velocity)
The Attempt at a Solution
I tried to set up a Bernoulli's equation for this, but there are 3 sections of the pipe, and I'm not sure how to add them together. I was looking for a solution and I saw Venturi's Effect, which just basically said that the pressure in the choked pipe is lower, and I don't know if it is even relevant.
But I know for sure that the height h2 got to do with the fluid kinetic energy in pipe C, but I don't know how to find the velocity in pipe C... Well, I tried to mix it around and ended up cancelling out and nothing remained. Really weird problem, given it just today that I learned about this guy's equation.
Thanks in advance