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During a phase transition, what is the nature of the material? |
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| Mar1-13, 10:30 AM | #1 |
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During a phase transition, what is the nature of the material?
As a material is heated, it increases in temperature until it enters a phase transition. During the transition, added heat does not increase the temperature. As this heat is being added, what is the substance? Is it a mixture of liquid and gas perhaps? If so, what are the proportions?
In other words, what exactly is the substance during one of the flat parts of the temperature vs. heat graph? http://www.physicstutorials.org/imag...ngeofwater.png |
| Mar1-13, 11:12 AM | #2 |
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If we look at water we would see molecules being given enough energy to overcome the bonds between them to turn into a gas. The proportions of gas and liquid is hard to determine, as this depends on how even something is heated, how hot the source is, if the gas can be lost from the container, and other factors. Heating water evenly in a sealed container is obviously different than boiling water on my stove at home.
But, assuming a perfectly sealed container I would expect the amount of gas to liquid ratio to increase as the amount of heat absorbed by the water increases. At a certain point practically all of the water would be a gas. However, as temperature is a measure of the average energy of the particles in a gas, I would expect there to be some liquid present at all times. |
| Mar1-13, 01:45 PM | #3 |
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| Mar1-13, 02:35 PM | #4 |
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During a phase transition, what is the nature of the material?
The graph shouldn't have sharp turns strictly. Even at 50 degrees there will be some water vapour in thermodynamic equilibrium, it's just a case of that gas/liquid ratio increasing very sharply as you approach 100 degrees. You'd visually see some molecules breaking free from the van der waals molecular interactions, then as the temperature increases, far more gain the kinetic energy necessary to break free.
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| Mar1-13, 05:31 PM | #5 |
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| Mar1-13, 06:37 PM | #6 |
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Your answers are highly confusing Chester. Of course 100°C is a special point for water (at atmospheric pressure), this is where the phase transition of water from liquid to gas takes place under equilibrium conditions. Yes overheating is possible up to the point where the p(V) curve changes slope, but this is not an equilibrium state and there are strong thermodynamic reasons why substances have a boiling point. Just because there is always some vapour pressure doesn't change that fact. The way you phrase it is sounds more like the behaviour behind the critical point, where there is indeed no difference any more between liquid and solid.
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| Mar1-13, 07:31 PM | #7 |
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http://www.google.com/imgres?imgurl=...9QEwAA&dur=557 Displayed on the figure the various percentages of saturated liquid and saturated vapor present as a function enthalpy of the mixture at each equilibrium temperature (the green lines). Note also that there is no special significance ascribed to 100 C, 1 atm. on the figure. |
| Mar2-13, 08:57 AM | #8 |
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Well I don't see how that graph is supposed to prove your point. On the right you have the constant pressure lines. The lowest one is for atmospheric pressure. If you are coming from the right you start with gas. When you remove Energy/Enthalpy by cooling, you move down the line and the temperature is dropping until the temperature drops to 100°C. When you remove more energy you move on the horizontal red line to the left, so the temperature stays at 100°C while the gas/liquid fraction drops (which is indicated by crossing the green lines) until all the water is liquid. All the rest of the diagram is for different pressures. So 100°C is the very special temperature at atmospheric pressure, where the constant pressure line for 1 atm touches the dome. At other pressures the phase transition happens at other temperatures and above the critical point there is no phase transition.
Vapour pressure has more to do with the Maxwell tail of the Boltzmann distribution so you always have some part of the water in the energetically less favourable state, but there is a sharp phase transition none the less. That is the whole idea of a phase transition. |
| Mar2-13, 10:24 AM | #9 |
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Here is a link to a pressure-enthalpy diagram for water which illustrates this with finer resolution. http://www.google.com/imgres?imgurl=...QEwBA&dur=8216 Also shown in the figure are the specific fractions of saturated vapor and liquid during the transition. |
| Mar3-13, 03:46 PM | #10 |
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| Mar3-13, 04:15 PM | #11 |
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This is a very interesting question.
When a substance is at a phase transition temperature it means that two phases are in thermal equilibrium. e.g. at boiling point: where , what this means is that the gas phase is in perfect equilibrium with the liquid phase. In molecular terms: this means that the number of molecules escaping the surface of the liquid and becoming gas ('evaporating') is exactly matched by the number of molecules colliding with the liquid surface and 'joining' the liquid phase ('condensing'). |
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