Neutron-Atom Collision: Energy Transfer

In summary, the conversation discusses an elastic collision between a neutron and an atom, where the atomic nucleus is initially at rest. It is assumed that the mass of the nucleus is about 13.2 times the mass of the neutron. The question is posed about the fraction of kinetic energy transferred from the neutron to the atomic nucleus in this collision. The concept of conservation in elastic collisions is also mentioned.
  • #1
bgil1989
1
0
1. A neutron in a reactor makes an elastic head-
on collision with the nucleus of an atom ini-
tially at rest.
Assume: The mass of the atomic nucleus is
about 13.2 the mass of the neutron.
What fraction of the neutron’s kinetic en-
ergy is transferred to the atomic nucleus?
 
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  • #2


bgil1989 said:
1. A neutron in a reactor makes an elastic head-
on collision with the nucleus of an atom ini-
tially at rest.
Assume: The mass of the atomic nucleus is
about 13.2 the mass of the neutron.
What fraction of the neutron’s kinetic en-
ergy is transferred to the atomic nucleus?

Welcome to PF.

What do you know about elastic collisions?

What gets conserved?
 
  • #3


In this scenario, the neutron's kinetic energy is transferred to the atomic nucleus through an elastic head-on collision. The amount of energy transferred will depend on the mass of the nucleus compared to the mass of the neutron. Since the mass of the nucleus is about 13.2 times greater than the mass of the neutron, the transfer of energy will be significant.

To calculate the exact fraction of energy transferred, we can use the formula for elastic collisions, which states that the initial kinetic energy of the system is equal to the final kinetic energy. In this case, the initial kinetic energy is solely from the neutron and the final kinetic energy is shared between the neutron and the nucleus.

We can express this as:

(1/2)mv^2 = (1/2)(mv^2) + (1/2)(Mv^2)

Where m is the mass of the neutron, v is its initial velocity, and M is the mass of the nucleus.

Solving for the fraction of energy transferred (E) we get:

E = [(1/2)(m/M)] / [(1/2)(m/M) + 1]

Plugging in the values given, we get:

E = [(1/2)(1/13.2)] / [(1/2)(1/13.2) + 1]

E = 0.038 or approximately 3.8% of the neutron's kinetic energy is transferred to the atomic nucleus in an elastic head-on collision.

This transfer of energy is important in understanding the behavior of particles in nuclear reactions and can have significant implications in fields such as nuclear energy and particle physics. Further studies and experiments can help us better understand and utilize the energy transfer in neutron-atom collisions.
 

1. What is a neutron-atom collision?

A neutron-atom collision is a type of nuclear reaction where a neutron collides with an atom, causing changes in the atom's nucleus and resulting in the formation of new particles.

2. How does energy transfer occur during a neutron-atom collision?

During a neutron-atom collision, energy is transferred from the neutron to the atom. This can happen through various processes such as elastic scattering, inelastic scattering, and nuclear reactions.

3. What factors affect the amount of energy transferred in a neutron-atom collision?

The amount of energy transferred in a neutron-atom collision depends on factors such as the energy and speed of the incoming neutron, the type and mass of the target atom, and the angle of collision.

4. Can energy be transferred from an atom to a neutron during a collision?

Yes, in some cases, energy can be transferred from an atom to a neutron during a collision. This can happen through processes such as nuclear reactions or inelastic scattering.

5. What are some real-world applications of neutron-atom collisions and energy transfer?

Neutron-atom collisions and energy transfer are essential in various fields such as nuclear power generation, medical imaging and treatment, and materials science. They are also used in research to study the properties of atomic nuclei and subatomic particles.

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