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Change of variable in integral of product of exponential and gaussian functions |
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| Dec24-12, 07:46 PM | #1 |
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Change of variable in integral of product of exponential and gaussian functions
I have the integral
[itex]\int_{-\infty}^{\infty}dx \int_{-\infty}^{\infty}dy e^{-\xi \vert x-y\vert}e^{-x^2}e^{-y^2}[/itex] where [itex]\xi[/itex] is a constant. I would like to transform by some change of variables in the form [itex]\int_{-\infty}^{\infty}dx F(x) \int_{-\infty}^{\infty}dy G(y)[/itex] the problem is that due to absolute value in the integral one must take in account where x is greater or less than y, can someone help me, please? |
| Dec25-12, 04:18 AM | #2 |
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Recognitions:
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First observe that
[itex]e^{-\xi \vert x-y\vert}e^{-x^2}e^{-y^2}=e^{-\xi \vert x-y\vert}e^{-(x-y)^2/2}e^{-(x+y)^2/2}[/itex] Then you can either change variables such as u=(x+y)/sqrt(2) v=(x-y)/sqrt(2) or break into two regions x<y x>y |
| Dec26-12, 03:06 AM | #3 |
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Hi !
the clolsed form of the integral involves a special function (erf). |
| Dec26-12, 08:32 AM | #4 |
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Change of variable in integral of product of exponential and gaussian functions
Nice trick! Thank you so much!
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