Finding time and final velocity

In summary, a photographer in a helicopter accidentally drops a camera from a height of 60.0 m while ascending at 12.5 m/s. Using the equations of motion, the camera will take 3.5 seconds to reach the ground and will have a final velocity of 33.67 m/s. However, this calculation assumes that the initial velocity of the camera is 0, which is not the case as the camera is dropped from a moving helicopter. Therefore, the calculated results may not be accurate.
  • #1
physfall
1
0

Homework Statement


A photographer in a helicopter ascending vertically at a constant rate of 12.5 m/s accidentally drops a camera out the window when the helicopter is 60.0 m above the ground.
-How long will it take the camera to reach the ground? What will its speed be when it hits?
a= -9.8 m/s^2 displacement=60 m

Homework Equations


(final v)^2=(initial v)^2 + 2*a*deltax
deltax=1/2a(t^2)+(initial v*t)



The Attempt at a Solution


initial v=0
so time will equal 3.5 s, and final velocity will equal 33.67 m/s^2
however, these are incorrect
 
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  • #2
The initial v is not 0, but the v of the helicopter and photographer. If you don't believe is, look up some movies of a ball shot from a moving car: when the car is moving at 50 km/h and the ball is shot backwards at 50 km/h, it drops straight down.
 
  • #3
calculations.



I would approach this problem by first identifying the relevant equations and variables. In this case, we are dealing with motion under constant acceleration, so the equations of motion for constant acceleration will be useful. The variables in this problem are the initial velocity (which is 12.5 m/s and is given), the final velocity (which we need to find), the acceleration (which is -9.8 m/s^2 due to gravity), and the displacement (which is 60 m and is given).

Using the equation (final v)^2=(initial v)^2 + 2*a*deltax, we can solve for the final velocity. Plugging in the values, we get (final v)^2 = (12.5 m/s)^2 + 2*(-9.8 m/s^2)*(60 m) = 1562.5 m^2/s^2. Taking the square root of both sides, we get the final velocity to be 39.5 m/s.

Next, to find the time it takes for the camera to reach the ground, we can use the equation deltax=1/2a(t^2)+(initial v*t). Plugging in the values, we get 60 m = 1/2*(-9.8 m/s^2)*(t^2) + (12.5 m/s)*(t). This is a quadratic equation, and solving for t using the quadratic formula, we get t = 4.04 s (rounded to the nearest hundredth).

Therefore, it will take 4.04 seconds for the camera to reach the ground and its speed will be 39.5 m/s when it hits.
 

1. What is time in relation to finding final velocity?

Time is a crucial factor in determining the final velocity of an object. It refers to the duration or period between the initial and final states of an object's motion. It is typically measured in seconds (s) or fractions of a second.

2. How do you calculate final velocity?

Final velocity can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Alternatively, it can also be calculated using the equation v^2 = u^2 + 2as, where s is the displacement of the object.

3. What is the difference between average and instantaneous velocity?

Average velocity refers to the total displacement of an object over a specific period of time, while instantaneous velocity refers to the velocity of an object at a specific moment. Average velocity is calculated by dividing the total displacement by the time taken, while instantaneous velocity can be calculated using calculus by finding the slope of the tangent line to the object's position-time graph at a specific time point.

4. How does acceleration affect final velocity?

Acceleration plays a crucial role in determining the final velocity of an object. If an object is accelerating, its velocity will change over time. The greater the acceleration, the faster the object's velocity will change, resulting in a higher final velocity. On the other hand, if an object is decelerating, its velocity will decrease over time, resulting in a lower final velocity.

5. Can final velocity be negative?

Yes, final velocity can be negative. This indicates that the object is moving in the opposite direction of its initial velocity. For example, if an object is initially moving to the right with a velocity of +10 m/s and then starts moving to the left with a final velocity of -5 m/s, the final velocity is negative. This is also known as a negative acceleration or deceleration.

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