- #1
Joe26
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Homework Statement
An object moves with constant acceleration 4.60 m/s2 and over a time interval reaches a final velocity of 10.0 m/s. If its initial velocity is −5 m/s, what is its displacement during the time interval? What is the total distance travelled?
a=4.60m/s^2
vi=-5 m/s
vf=10m/s
Homework Equations
vf= (vi)+(a)(t)
deltax=(vi)(t) + 1/2(a)(t)^2
The Attempt at a Solution
vf=vi+at
10=-5+(4.6)t
t=3.26 s
deltax= vit+1/2(a)(t)^2
deltax= (-5)(3.26)+1/2(4.6)(3.26)^2
deltax= 8.14 m (displacement)
total distance traveled = 8.14 m
the answer i got for displacement is correct but the total distance traveled is wrong and i can't figure out why. can anyone help me please?