Does this function belong to an interesting class of functions?

In summary, the function f(\phi) = \frac {1 - \phi}{\phi - 1} has a value of -1 except when \phi = 1, where it is undefined. There is a similar function, the Mobius transformation, that has applications but is usually used with complex numbers. While the function may have some interesting implications in certain situations, it is not commonly used.
  • #1
PhilDSP
643
15
Hello and thanks for your consideration,

I'd like some insight into the function [itex]f(\phi) = \frac {1 - \phi}{\phi - 1}[/itex]

Does this apply to any known modeling situations? Is it recognized as belonging to a more general class of functions that may have interesting or unique characteristics? Or can the function be transformed into a function that does?
 
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  • #2
Your function, as written, is just equal to -1, except when [itex]\phi = 1[/itex], where there is a discontinuity because the denominator vanishes there.

If you want an example of a function that has a similar form but isn't trivially some constant and has some applications, see Mobius transformation. (But note that the Mobius transformation is usually used with complex numbers. I don't know if it is used much in real number applications).
 
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  • #3
Thanks, an association with the Mobius transformation does yield many interesting things to think about, especially since [itex]\phi[/itex] can be complex in the situation where the function popped up.

We could argue that the value becomes 1 when [itex]\phi = 1[/itex] couldn't we? This almost sounds like a spinning sphere where the axis must be aligned parallel to a force acting on the sphere, but which can suddenly undergo a spin flip.
 
  • #4
PhilDSP said:
We could argue that the value becomes 1 when [itex]\phi = 1[/itex] couldn't we?

No, you can't define a function one way and then argue that it has a different definition. You can, however, define a function that is 1 when [itex] \phi = 1 [/itex] and equal to -1 elsewhere. You can argue that this definition applies to a certain practical situation. That would be an argument about physics.
 
  • #5
PhilDSP said:
We could argue that the value becomes 1 when [itex]\phi = 1[/itex] couldn't we?

No. "f(x)= -1" and "g(x)= -1 if [itex]x\ne 1[/itex], and is not defined at [itex]x= 1[/itex]" are two different functions.
 

1. What makes a function belong to an interesting class of functions?

The criteria for determining whether a function belongs to an interesting class of functions can vary depending on the field of study and the specific application. However, some common characteristics of interesting functions may include their ability to model real-world phenomena, their simplicity or elegance, their usefulness in solving mathematical problems, or their unique properties and behaviors.

2. How can we identify if a function belongs to an interesting class of functions?

To identify whether a function belongs to an interesting class, we can analyze its properties and compare them to known classes of functions. We can also study its behavior, such as its rate of change, symmetry, or periodicity, to determine if it exhibits interesting patterns or relationships. Additionally, we can consider the context in which the function is being used and evaluate its relevance and significance in that particular field.

3. Are there different levels of "interesting" when it comes to classifying functions?

Yes, there can be different levels of "interesting" when classifying functions. Some functions may be deemed interesting due to their simple yet powerful properties, while others may be considered interesting for their complexity and ability to model intricate systems. Additionally, a function may be considered interesting in one field of study, but not as much in another.

4. Can a function belong to multiple interesting classes?

Yes, a function can belong to multiple interesting classes. For example, a function can be both periodic and symmetrical, making it interesting in both those classes. Additionally, a function may have properties that allow it to be classified in different ways, making it interesting in multiple categories.

5. Why is it important to determine if a function belongs to an interesting class?

Determining if a function belongs to an interesting class can provide valuable insights and understanding in various fields, such as mathematics, physics, and engineering. It can also help us identify patterns and relationships between different functions and assist in problem-solving and modeling real-world phenomena. Additionally, studying interesting functions can lead to new discoveries and advancements in scientific research.

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