Calculate Area with D:d:p = 4:1:4

[hpla]

hey >>>

i want to Calculate this area Equation :

A= pi *(D^2*d^2)*p*n*k

n= 0.5
k=0.4

but the Valuable of ( D-d-p) given like this :

D:d:p
4 1 4

My question is :

i don't understand Valuable of ( D-d-p)

is it Number or proportion ... just can anyone make it clear to me

Please, Please, Please,

 

[SteamKing]

It looks like a series proportion to me. D and p are each 4 times the value of d.

 

[hpla]

Thank you for your response .. u mean

D= 4d P=4d

 

[SteamKing]

Yes.

 

[CellCoree]

Please

Hello,

Thank you for reaching out with your question. It seems like you are trying to calculate the area using an equation that involves the values of D, d, and p. The values given for D, d, and p are in a ratio of 4:1:4. This means that for every 4 units of D, there is 1 unit of d and 4 units of p.

To calculate the actual values of D, d, and p, you would need to know the value of one of the variables. For example, if we know that D = 4, then we can find the values of d and p by using the ratio. d would be 1/4 of 4, which is 1, and p would be 4/4 of 4, which is also 4.

Once you have the values of D, d, and p, you can plug them into the equation you provided to calculate the area. However, I am not sure what the values of n and k represent in your equation, so I cannot provide a specific answer.

I hope this helps clarify the values of D, d, and p for you. If you have any further questions, please let me know. Thank you.