- #1
ND3G
- 79
- 0
3x+3y+3z=3
x+y+z=-1
3 3 3 | 3
1 1 1 |-1
1 1 1 | 0
0 0 0 | 1
x = -y -z
y = 1
Substitute y into x, x = -1 -z
Let z = t, tER
Then x = -1 -t, y = 1
The corresponding vector equation of the line intersection is:
(x,y,z) = (-1, 1, 0) + t(-1, 0, 1)
Does that look right? This is my first time dealing with these.
x+y+z=-1
3 3 3 | 3
1 1 1 |-1
1 1 1 | 0
0 0 0 | 1
x = -y -z
y = 1
Substitute y into x, x = -1 -z
Let z = t, tER
Then x = -1 -t, y = 1
The corresponding vector equation of the line intersection is:
(x,y,z) = (-1, 1, 0) + t(-1, 0, 1)
Does that look right? This is my first time dealing with these.