Find the hamiltonian and lagrangian of a chained system

In summary, we have found the Hamiltonian and Lagrangian of a chain of N points at distance a each other, and can now use them to further analyze the system.
  • #1
martyf
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Homework Statement


N points at distance a each other -> chain length L=Na. q[tex]_{}n[/tex]
is the n-point shift.

Homework Equations



q[tex]\stackrel{}{}..[/tex][tex]_{}n[/tex]=[tex]\Omega[/tex][tex]^{}2[/tex](q[tex]_{}n+1[/tex]+q[tex]_{}n-1[/tex]-2q[tex]_{}n[/tex]

I must find the hamiltonian and lagrangian of the system.

The Attempt at a Solution


 
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  • #2


To find the Hamiltonian and Lagrangian of this system, we first need to define our variables and parameters. Let N be the number of points in the chain, a be the distance between each point, and L be the total length of the chain.

The Hamiltonian of a system is defined as the total energy of the system, which is equal to the sum of the kinetic and potential energies. In this case, the kinetic energy can be written as the sum of the kinetic energies of each individual point in the chain:

K = 1/2 * m * v^2 = 1/2 * m * (dq/dt)^2

where m is the mass of each point and v is its velocity. Since each point in the chain is connected to the next one by a spring with a spring constant k, the potential energy can be written as:

U = 1/2 * k * (q_n+1 - q_n - a)^2

where q_n is the displacement of the n-th point from its equilibrium position.

Therefore, the Hamiltonian of the system can be written as:

H = K + U = 1/2 * m * (dq/dt)^2 + 1/2 * k * (q_n+1 - q_n - a)^2

Now, to find the Lagrangian, we need to define the generalized coordinates and their time derivatives. In this case, we can choose the displacement of each point from its equilibrium position as the generalized coordinates, and their time derivatives as the generalized velocities:

q_n = q_n
dq_n/dt = v_n

Using these generalized coordinates and velocities, the Lagrangian can be written as:

L = K - U = 1/2 * m * v_n^2 - 1/2 * k * (q_n+1 - q_n - a)^2

Finally, we can express the Lagrangian in terms of the generalized coordinates and their time derivatives:

L = 1/2 * m * (dq/dt)^2 - 1/2 * k * (q_n+1 - q_n - a)^2

This is the Hamiltonian and Lagrangian of the given system. From here, we can use the Euler-Lagrange equations to derive the equations of motion for the system.
 

1. What is the Hamiltonian of a chained system?

The Hamiltonian of a chained system is a function that describes the total energy of the system. It is defined as the sum of the kinetic and potential energies of all the individual particles in the system.

2. How is the Hamiltonian different from the Lagrangian?

The Hamiltonian and Lagrangian are two different mathematical approaches used to describe the dynamics of a physical system. The Hamiltonian is based on the total energy of the system, while the Lagrangian is based on the difference between the kinetic and potential energies of the system.

3. How do you find the Hamiltonian of a chained system?

To find the Hamiltonian of a chained system, you first need to determine the kinetic and potential energies of each individual particle in the system. Then, you can use the formula H = T + V, where H is the Hamiltonian, T is the kinetic energy, and V is the potential energy.

4. What are the advantages of using the Hamiltonian and Lagrangian to describe a system?

The Hamiltonian and Lagrangian approaches are advantageous because they provide a more systematic and elegant way of describing the dynamics of a system compared to using Newton's laws of motion. They also allow for the use of advanced mathematical techniques, such as variational methods, in solving complex problems.

5. Can the Hamiltonian and Lagrangian be used for any type of physical system?

Yes, the Hamiltonian and Lagrangian can be used for any type of physical system, as long as the system can be described in terms of its energy and the forces acting on it. They are commonly used in classical mechanics, quantum mechanics, and other areas of physics.

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