| New Reply |
Shedding some light on the dot product |
Share Thread | Thread Tools |
| Jan15-13, 08:23 PM | #1 |
|
|
Shedding some light on the dot product
The dot product A . B is the magnitude of vector A times the projection of B onto A.
B . A is the magnitude of vector B times the projection of A onto B. Correct? A . B = B . A and this makes sense. But, say you're trying to find the components of a vector V in the direction of a vector W. Would it matter whether or not you wrote V . W or W . V? EDIT: Also, does anyone know what it means (geometrically speaking) to find the components of a vector in the direction of another vector? I can give an example from a book if needed. |
| Jan15-13, 08:56 PM | #2 |
|
|
To the first question, no it wouldn't matter. The dot product is commutative so ##\vec{V} \cdot \vec{W} = \vec{W} \cdot \vec{V}## for any vectors V and W.
To the edit, imagine you have your vector lying in the plane. Now imagine it is the hypotenuse of a right triangle where one of the sides of the triangle is parallel to the x-axis and the other side is parallel to the y-axis. The component of the main vector (which remember is represented as the hypotenuse) in the x direction is the length of the side of the triangle parallel to the x-axis, and the same for the y direction. |
| Jan16-13, 08:03 AM | #3 |
|
|
You need to multiply V by the unit vector along W. So the magnitude of the projection is given by V.W/W |
| New Reply |
| Thread Tools | |
Similar Threads for: Shedding some light on the dot product
|
||||
| Thread | Forum | Replies | ||
| Wind Actions - Vortex Shedding | Mechanical Engineering | 4 | ||
| Intelligent Load shedding system | Electrical Engineering | 0 | ||
| Shedding the fat | General Discussion | 4 | ||