whats the derivative of sin^2(theta)?

but i need the derivative wrt time where theta depends on time
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Mentor
 Quote by M. next but i need the derivative wrt time where theta depends on time
Use the chain rule.
$$\frac{d}{dt}sin^2(\theta) = \frac{d}{d\theta}sin^2(\theta)\cdot \frac{d\theta}{dt} = ?$$
 then it is simply 2sin(theta)cos(theta)*(theta dot)

Mentor

Yes, that's it.