- #1
bmed90
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Why can you Take out An E^xy??
Im learning about implicit solutions for differential equations. Anyways I took the derivative of a relation containing x and y to get
dy/dy=1-e^xy(y)/ e^xy(x)+1
Anywhoo it turns out to be a solution to the diff eq dy/dy = e^-xy - y/ e^-xy + x
Apparently you can take out an e^xy from dy/dy=1-e^xy(y)/ e^xy(x)+1 in order to get to
dy/dy = e^-xy - y/ e^-xy + x
How exactly is this so? How does this work...I hope you understand my question
Homework Statement
Im learning about implicit solutions for differential equations. Anyways I took the derivative of a relation containing x and y to get
dy/dy=1-e^xy(y)/ e^xy(x)+1
Homework Equations
Anywhoo it turns out to be a solution to the diff eq dy/dy = e^-xy - y/ e^-xy + x
The Attempt at a Solution
Apparently you can take out an e^xy from dy/dy=1-e^xy(y)/ e^xy(x)+1 in order to get to
dy/dy = e^-xy - y/ e^-xy + x
How exactly is this so? How does this work...I hope you understand my question